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denpristay [2]
3 years ago
15

What are some examples of properties of water?

Chemistry
1 answer:
gavmur [86]3 years ago
4 0
Examples : cohesion , polarity , high specific heat , adhesion.<span />
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The specific heat of water is 4.18 j/(g⋅∘c). calculate the molar heat capacity of water. express your answer to three significan
iogann1982 [59]
Specific heat capacity of any substance comes with the unit : J/(g*degree C)
for molar capacity , change gram -> moles  unit ( J / moles * degree C)

4.18 J  / mol - degree C

H = 1.01 g * 2 =   2.02 g
O = 16 g

2.02 + 16  =  18.02  g

Now  :-    4.18  J / mol- degree C) *  18.02 /  1 mole H2O
molar heat  =  75.3 J / mol - degree C



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5 0
3 years ago
Read 2 more answers
Which of the following theories provides information concerning both molecular shape and molecular bonding?
Alinara [238K]

I believe the answer is orbital hybridization theory

7 0
3 years ago
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
Why do we need to be more careful of how we use our water
Reil [10]
That's why it's important for you to use water wisely and not to waste it. When you waste water, you're taking water that other people might need. But when you use water carefully, you leave more water for other people to use. It is also important to use water carefully because our weather can be unpredictable.
3 0
3 years ago
Read 2 more answers
3. A 4.00 gram sample of solid gold was heated from 274K to 314K. How much energy was involved?
MrMuchimi
Q = mcΔT = (4.00 g)(0.129 J/g•°C)(40.85 °C - 0.85 °C)
Q = 20.6 J of energy was involved (more specifically, 20.6 J of heat energy was absorbed from the surroundings by the sample of solid gold).
3 0
3 years ago
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