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Nadya [2.5K]
3 years ago
6

Students in Ms. Delgado’s science class built machines. They measured the input and output forces. The results of four students

are listed in the table.
Which lists the students in order from student whose machine has the least mechanical advantage to student whose machine has the greatest mechanical advantage?
Physics
2 answers:
puteri [66]3 years ago
7 0

Answer:D. Lian, Aida, Dipak, Brian

<h3>welcome</h3>

Explanation:

nordsb [41]3 years ago
4 0

The correct answer is

D. Lian, Aida, Dipak, Brian

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The center of the Milky Way galaxy lies in the direction of the _constellation, aboutlight-years away.
Elza [17]

Answer:

Sagittarius

Explanation:

The center of the Milky Way galaxy lies in the direction of the Sagittarius constellation, about 26,000 light-years away.

5 0
4 years ago
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Two metal disks, one with radius R1 = 2.45 cm and mass M1 = 0.900 kg and the other with radius R2 = 5.00 cm and mass M2 = 1.60 k
natima [27]

Answer:

part (a) a_1\ =\ 2.9\ kg

Part (b) a_2\ =\ 6.25\ kg

Explanation:

Given,

  • mass of the smaller disk = M_1\ =\ 0.900\ kg
  • Radius of the smaller disk = R_1\ =\ 2.45\ cm\ =\ 0.0245\ m
  • mass of the larger disk = M_2\ =\ 1.6\ kg
  • Radius of the larger disk =R_2\ =\ 5.0\ cm\ =\ 0.05\ m
  • mass of the hanging block = m = 1.60 kg

Let I be the moment of inertia of the both disk after the welding,\therefore I\ =\ I_1\ +\ I_2\\\Rightarrow I\ =\ \dfrac{1}{2}(M_1R_1^2\ +\ M_2R_2^2)\\\Rightarrow I\ =\ 0.5\times (0.9\times 0.0245^2\ +\ 1.6\times 0.05^2)\\\Rightarrow I\ =\ 2.27\times 10^{-3}\ kgm^2

part (a)

A block of mass m is hanging on the smaller disk,

From the f.b.d. of the block,

Let 'a' be the acceleration of the block and 'T' be the tension in the string.

mg\ -\ T\ =\ mg\\\Rightarrow T\ =\ mg\ -\ ma\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,eqn (1)

Net torque on the smaller disk,

\therefore \tau\ =\ I\alpha\\\Rightarrow TR_1\ =\ \dfrac{Ia}{R_1}\\\Rightarrow T\ =\ \dfrac{Ia}{R_1^2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,enq (2)

From eqn (1) and (2), we get,

mg\ -\ ma\ =\ \dfrac{Ia}{R_1^2}\\\Rightarrow a\ =\ \dfrac{mg}{\dfrac{I}{R_1^2}\ +\ m}\\\Rightarrow a\ =\ \dfrac{1.60\times 9.81}{\dfrac{2.27\times 10^{-3}}{0.027^2}\ +\ 1.60}\\\Rightarrow a\ =\ 2.91\ m/s^2

part (b)

In this case the mass is rapped on the larger disk,

From the above expression of the acceleration of the block, acceleration is only depended on the radius of the rotating disk,

Let 'a_2' be the acceleration of the block in the second case,

From the above expression,

\therefore a\ =\ \dfrac{mg}{\dfrac{I}{R_1^2}\ +\ m}\\\Rightarrow a\ =\ \dfrac{1.60\times 9.81}{\dfrac{2.27\times 10^{-3}}{0.05^2}\ +\ 1.60}\\\Rightarrow a\ =\ 6.25\ m/s^2

5 0
3 years ago
A boater is floating 1060 meters down a river. The person takes 40 minutes. At what speed is the boat moving?
Mashutka [201]
26.5, I’m not sure if it’s right but 1060/40 gets that
7 0
3 years ago
The morning of a birthday party, a balloon is filled with 8.5 L of helium (He) when the temperature is 294 kelvin. The party sta
Phoenix [80]

Explanation:

the morning of the birthday party balloon filled with the 2.5 Litre of helium

temperature is 294kelvin

the party starts at the 4 p.m.

temperature rises 305 Kelvin.

the new volume = 4 litre.

At same temperature,

P

1

V

2

=P

2

V

2

(Boyle's law)

P

1

=10atm;P

2

=1atm

V

1

=4l=V

2

=8l

But while filling balloons from cylinder when pressure in cylinder becomes 1 atm then further filling is not possible (P

1

′

=9atm)

Let n be the number of balloons that can be filled.

∴P

1

′

V

1

=n(P

1

V

1

)

9×8=n(4×1)

n=

4

9×8

=18balloons

5 0
3 years ago
Which of the following is correct for speed?
Olin [163]

Answer:

Speed is a "scalar" quantity

(C) is the correct answer

An object could travel at 10 m/s to some point and then return to the origin at 10 m/s for an average speed of 10 m/s, however it's displacement over that time would be zero for a net velocity of zero.

4 0
2 years ago
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