Ask question

Ask question

All categories

3 years ago

15

Haw does density of a liquid vary with the temperature

2 answers:

cluponka [151]3 years ago

3 0

Answer:

as temperature cools density increases

Explanation:

Density is the ratio of mass to volume. When the temperature varies, the volume of the liquid changes. ... Also, cooling a substance causes molecules to slow down and get slightly closer together, occupying a smaller volume that results in an increase in density.

liraira [26]3 years ago

3 0

Yes she’s correct Density is the ratio of mass to volume.

You might be interested in

PLEASE HELP TIME SENSITIVE:)

gladu [14]

it is C....................

8 0

2 years ago

Read 2 more answers

hich best explains why no current is induced? The wire needs to be coiled less tightly. The wire needs to be straight, not coile

Dahasolnce [82]

The magnet needs to be held above the coils of wires

7 0

3 years ago

A storage tank containing oil (SG=0.92) is 10.0 meters high and 16.0 meters in diameter. The tank is closed, but the amount of o

blagie [28]

Answer:

a-1 Graph is attached. The relation is linear.

a-2 The corresponding height for 68 kPa Pressure is 7.54 m

a-3 The corresponding weight for 68 kPa Pressure is 1394726kg

b The original height of the column is 5.98 m

Explanation:

Part a

a-1

The graph is attached with the solution. The relation is linear as indicated by the line.

a-2

By the equation

$P=\rho \times g \times h$

Here

P is the pressure which is given as 68 kPa.
ρ is the density of the oil whose SG is 0.92. It is calculated as

$\rho=S.G \times \rho_{water}\\\rho=0.92 \times 1000 kg/m^3\\\rho=920 kg/m^3\\$

g is the gravitational constant whose value is 9.8 m/s^2
h is the height which is to be calculated

$P=\rho \times g \times h\\h=\frac{P}{\rho \times g}\\h=\frac{68 \times 10^3}{920 \times 9.8}\\h=7.54m$

So the height of column is 7.54m

a-3

By the relation of volume and density

$M=\rho \times V$

Here

ρ is the density of the oil which is 920 kg/m^3
V is the volume of cylinder with diameter 16m calculated as follows

$V=\pi r^2h\\V=3.14\times (8)^2 \times 7.54\\V=1515.23 m^3$

Mass is given as

$M=\rho \times V\\M=920 \times 1515.23\\M=1394726kg$

So the mass of oil leading to 68kPa is 1394726kg

Part b

Pressure variation is given as

$\Delta P=P_{obs}-P_{atm}\\\Delta P=115-101 kPa\\\Delta P=14 kPa\\$

Now corrected pressure is as

$P_c=P_g-\Delta P\\P_c=68-14 kPa\\P_c=54 kPa$

Finding the value of height for this corrected pressure as

$P_c=\rho \times g \times h\\h=\frac{P_c}{\rho \times g}\\h=\frac{54 \times 10^3}{920 \times 9.8}\\h=5.98m$

The original height of column is 5.98m

4 0

3 years ago

When two waves are moving toward each other, and their crests line up with each other, it results in a wave with greater amplitu

Maurinko [17]

constructive interference

4 0

3 years ago

Why do we use the name electromagnetism to describe the force of an

ElenaW [278]

Answer:

magnet, gravity

Explanation:

5 0

3 years ago