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Leto [7]
3 years ago
9

Convert 3.65 moles to molecules ( 6.02* 10^23= 1 mole)

Chemistry
1 answer:
Kitty [74]3 years ago
6 0
Just multiple the two. 3.65x6.02*10^23
2.197x10^24
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For the reaction, 2cr2+ + cl2(g) ---> 2cr3+ + 2cl- e cell (standard conditions) = 1.78v calculate ecell (standard conditions)
PolarNik [594]

Answer:

-1.78 V

Explanation:

There are several rules required to calculate the cell potential:

  • given standard cell potential, we may reverse the equation: the products of a given reaction become our reactants, while reactants become our products in the reversed equation. For a reversed equation, we change the sign of the cell potential to the opposite sign;
  • if we multiply the whole equation by some number, this doesn't influence the cell potential value. It only produces a different expression in the equilibrium constant.

That said, notice that the initial reaction with respect to the final reaction is:

  • reversed: chromium(III) cation and chloride anion become our reactants as opposed to the products in the initial reaction, so we change the sign of the cell potential to a negative value of -1.78 V;
  • each coefficient is multiplied by a fraction of \frac{1}{2}. It doesn't influence the value of the cell potential.

Thus, we have a cell of E = -1.78 V.

3 0
3 years ago
How much heat is transferred when 7.19 grams of H2 reacts with excess nitrogen, according to the following equation: N2(g) + 3 H
nikdorinn [45]

Answer:

Q=54.8kJ

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:

\Delta H=\frac{46.2kJ}{mol} *\frac{1mol}{3molH_2}\\\\ \Delta H=15.4\frac{kJ}{molH_2}

Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:

Q=7.19gH_2*\frac{1molH_2}{2.02gmolH_2}*15.4\frac{kJ}{molH_2} \\\\Q=54.8kJ

Best regards!

5 0
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carbon has 6 protons and hydrogen has 1 proton

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Determine the highest occupied energy level in the
motikmotik
He, because it’s a noble gas which they have full valence electrons (occupied energy levels)
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