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Scorpion4ik [409]

3 years ago

8

What happens to the volume when we INCREASE the pressure?

1 answer:

docker41 [41]3 years ago

6 0

Answer:

What happens to the volume when we INCREASE the pressure?

When the pressure increases the volume decreases, this best explain boyle's law which describe an increase in volume results to a decrease in pressure vice versa

Explanation:

You might be interested in

Express the frequency in inverse seconds. n=5-->n=1

Natalija [7]

The frequencies expressed in inverse seconds are 5 s⁻¹ and 1 s⁻¹.

<h3>What is frequency?</h3>

Frequency is the number of complete cycles in a second made by a wave.

F = 1/T

F = n/t

<h3>When n = 5</h3>

F = 5/s = 5 s⁻¹ = 5Hz

<h3>When n = 1</h3>

F = 1/s = 1 s⁻¹ = 1Hz

Learn more about frequency here: brainly.com/question/254161

#SPJ1

4 0

1 year ago

1. Calculate the momentum of a 1,500 kg car traveling at 6 m/s.

ziro4ka [17]

Answer:

1. $9000kgm/s$

2. $258,000kgm/s$

Explanation:

1.Momentum is given as the product of mass by velocity of an object.

Momentum, $p=mv$

m=1,500kh, v=6m/s

$p=1500*6\\p=9000kgm/s$

2.Momentum, $p=mv$

m=7800kg, v=30m/s

$p_1=7800*30\\p_1=234,000kgm/s\\$

new mass=7800+800=8600

As mass is increased, so does the resultant velocity as mass is directly proportional to velocity.

$p_2=8600*30\\p_2=258,000kgm/s$

8 0

3 years ago

What is the oxidation number of cl− in the hypochlorite ion clo−?

mariarad [96]

Answer : The oxidation number of chlorine (Cl) is, (+1)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in peroxides.

The oxidation number of a Group 1 element in a compound is +1.

The oxidation number of a Group 2 element in a compound is +2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is, $ClO^-$

Let the oxidation state of 'Cl' be, 'x'

$x+(-2)=-1\\\\x-2=-1\\\\x=+1$

Therefore, the oxidation number of chlorine (Cl) is, (+1)

5 0

3 years ago

At the end of the last lesson, you learned there was not enough carbon dioxide in the biodome air, which led to a decrease in en

lakkis [162]

There may be too many plants present or too few animals in the biodome hence the decrease in carbon dioxide .

<h3>What is a biodome?</h3>

The term biodome refers to an artificially buit ecosystem. We must recall that an ecosystem is a self sustaining unit in which materials and energy are exchanged.

If there is less carbon dioxide in the biodome then it means that there are too many plants present or too few animals in the biodome.

Learn more about ecosystem: brainly.com/question/1673533

4 0

2 years ago

When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu

Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0

3 years ago