A double displacement reaction is one in which the positive and negative ion in one reactant switch places with the positive and negative ions of the second reactant forming two new products.
In general if we have two reactants AB and CD, the double displacement reaction can form the following products:
A⁺B⁻ + C⁺D⁻ → C⁺B⁻ + A⁺D⁻
In the given example:
K₂SO₄ + Pb(NO₃)₂ → PbSO₄ + 2KNO₃
Ans: B)
One of the products would be PbSO₄
Answer: PH= 1.4
Explanation:
n(mole)= concentration(c)× volume(v)
n(HClO4) = 0.08 ×0.03
n(HClO4)= 0.0024 mole
n(Ba(OH)2) = 0.28 × 0.05
n(Ba(OH)2) = 0.014
2HClO4 + Ba(OH)2.....>Ba(ClO4)2 + 2H2O.
Hence, the limiting reagent is perchloric acid. According to the reaction:
0.0024 HClO4 req 1/2× 0.0024 of Ba(OH)2.
n(Ba(OH) reacted= 0.0012
Excess n(Ba(OH)2) = 0.014-0.0012
Excess n(Ba(OH)2) = 0.0128
Conc(Ba(OH)2) unreacted = 0.0128/.32 (vol. of mix is 32ml)
= 0.04M = [H+]
PH = -log[0.04] = 1.397
PH= 1.4
Plate Tectonics is the theory that earths outer shell is divided into several plates that glide over the mantle.
I'll balance it for you :D
HNO3 + P → <span>H3PO4 + NO
break it down first (to see how many of each atom on each side) so
H- 1 H-3
N-1 N-1
O-3 O-12
P-1 P-3
now u gotta make the numbers equal on both sides
make the first H 3 so it's balanced with the other one by putting a 3 in front of it in the equation like this:
</span>3HNO3 + P → H3PO4 + NO
<span>
that changes the WHOLE equation except the P because it's not attached (so now the N is also 3 and the O as well)
</span>H- 3 H-3
N-3 N-1
O-9 O-12
P-1 P-3
so now the N is imbalanced on the product side, so do the same thing to fix it
3HNO3 + P → H3PO4 + 3NO
the O next to the N is now also 3 sooo
H- 3 H-3
N-3 N-3
O-9 O-15
P-1 P-3
3HNO3 + 3P → H3PO4 + 3NO
H- 3 H-3
N-3 N-3
O-9 O-15
P-3 P-3
3HNO3 + 3P → H3PO4 + 3NO
i realized halfway through this that the O is still unbalanced SOMEHOW
Erosion or Weathering. Probably erosion.
