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FinnZ [79.3K]
3 years ago
6

Poseen ocho, electrones de valencia, exepto el helio que tiene solo dos. Estan ubicados en el grupo VIIIA o 18. Son conocidos ta

mbien como gases inertes.
A. Metaloides
B. No metales
C. Gases Nobles.​
Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

c

Explanation:

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ASAP..pls need help.....
zimovet [89]

Answer:

It releases nutrients which causes rapid growth of planktons which leads to oxygen deficiency leading to death of aquatic animals,a phenomenon known as eutrophication.

Explanation:

4 0
3 years ago
Which option is an example of a chemical property? Question options: reactivity color melting point density
White raven [17]

Hi there, the correct answer to this would be reactivity because color, melting point, and density are all examples of physical properties.

4 0
3 years ago
Read 2 more answers
Which of the five type of equilibrium problems best applies to this question: Consider the following reaction at equilibrium. Wh
andreev551 [17]

Answer:

d

Explanation:

3 0
3 years ago
What mass of radon is in 8.17 moles of radon?
Len [333]

Answer:

1813.74g

Explanation:

Given parameters:

Number of moles of radon  = 8.17moles

Unknown:

Mass of radon  = ?

Solution:

To solve this problem, we use the expression below:

      Number of moles = \frac{mass}{molar mass}  

Molar mass of radon  = 222g/mol

Now insert the parameters and solve;

    Mass of radon  = Number of moles x molar mass

                              = 8.17 x 222

                              = 1813.74g

4 0
3 years ago
Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100
vesna_86 [32]

<u>Answer:</u> The solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}

                      3s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2

We are given:

K_{sp}=2.5\times 10^{-33}

Putting values in above equation, we get:

2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L

Hence, the solubility of Cd_3(PO_4)_2 in water is 1.18\times 10^{-7}mol/L

6 0
3 years ago
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