Ask question

Ask question

All categories

3 years ago

6

Poseen ocho, electrones de valencia, exepto el helio que tiene solo dos. Estan ubicados en el grupo VIIIA o 18. Son conocidos ta

mbien como gases inertes.
A. Metaloides
B. No metales
C. Gases Nobles.

1 answer:

Salsk061 [2.6K]3 years ago

5 0

Answer:

c

Explanation:

You might be interested in

ASAP..pls need help.....

zimovet [89]

Answer:

It releases nutrients which causes rapid growth of planktons which leads to oxygen deficiency leading to death of aquatic animals,a phenomenon known as eutrophication.

Explanation:

4 0

3 years ago

Which option is an example of a chemical property? Question options: reactivity color melting point density

White raven [17]

Hi there, the correct answer to this would be reactivity because color, melting point, and density are all examples of physical properties.

4 0

3 years ago

Read 2 more answers

Which of the five type of equilibrium problems best applies to this question: Consider the following reaction at equilibrium. Wh

andreev551 [17]

Answer:

d

Explanation:

3 0

3 years ago

What mass of radon is in 8.17 moles of radon?

Len [333]

Answer:

1813.74g

Explanation:

Given parameters:

Number of moles of radon = 8.17moles

Unknown:

Mass of radon = ?

Solution:

To solve this problem, we use the expression below:

Number of moles = $\frac{mass}{molar mass}$

Molar mass of radon = 222g/mol

Now insert the parameters and solve;

Mass of radon = Number of moles x molar mass

= 8.17 x 222

= 1813.74g

4 0

3 years ago

Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100

vesna_86 [32]

<u>Answer:</u> The solubility of $Cd_3(PO_4)_2$ in water is $1.18\times 10^{-7}mol/L$

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

$Cd_3(PO_4)_2\rightleftharpoons 3Cd^{2+}+2PO_4^{3-}$

3s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Cd^{2+}]^3[PO_4^{3-}]^2$

We are given:

$K_{sp}=2.5\times 10^{-33}$

Putting values in above equation, we get:

$2.5\times 10^{-33}=(3s)^3\times (2s)^2\\\\2.5\times 10^{-33}=108s^5\\\\s=1.18\times 10^{-7}mol/L$

Hence, the solubility of $Cd_3(PO_4)_2$ in water is $1.18\times 10^{-7}mol/L$

6 0

3 years ago