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erma4kov [3.2K]
3 years ago
9

In an oxidation–reduction reaction, what happens to the electrons in the oxidation process? A. Electrons are bonded. B. Electron

s are gained. C. Electrons are lost. D. Electrons are replaced.
Chemistry
2 answers:
DanielleElmas [232]3 years ago
7 0

Answer: C. Electrons are lost.

Explanation:

  • The oxidation reduction reaction is between oxidizing agent and reducing agent.
  • The oxidizing agent gains electrons and reduction process occurs to it, while the reducing agent losses electrons and oxidation process occurs to it.
  • oxidizing agent + ne → product <em>"reduction process, gain electrons"</em>
  • reducing agent → product + ne<em> "oxidation process, loss electrons"</em>
  • Thus, The right answer is: in the oxidation process, electrons are lost.
ryzh [129]3 years ago
3 0
C electrons are lost. Oxidation is loss and reduction is gain
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The nucleus contains both protons and electrons True or false
Varvara68 [4.7K]

Answer: False

Explanation: The nucleus of an atom only contains the protons and neutrons.

The electrons are not found in the nucleus,

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1. Which change of state is accompanied by the removal of heat energy​
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4 0
3 years ago
Find the molar mass of this
kirill115 [55]

Explanation:

Given problem:

Find the molar mass of:

  SO₃ and C₁₀H₈

Solution:

The molar mass of a compound is the mass in grams of one mole of the substance.

To solve this, we are going to add the individual atomic masses of the elements in the compound;

  Atomic mass;

       S = 32g/mol; O = 16g/mol; C = 12g/mol and H = 1g/mol

For  SO₃;

     = 32 + 3(16)

     = 32 + 48

     = 80g/mol

For C₁₀H₈

      = 10(12) + 8(1)

      = 120 + 8

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7 0
3 years ago
What is the mass, in grams, 200mL of liquid with a density of 1.4g/mL
Tcecarenko [31]

The mass of the liquid is 280 g.

Mass = 200 mL × (1.4 g/1 mL) = 280 g

6 0
3 years ago
10 points. Please help.
ratelena [41]

Answer:

-191.7°C

Explanation:

P . V = n . R . T

That's the Ideal Gases Law. It can be useful to solve the question.

We replace data:

2.5 atm . 8 L = 3 mol . 0.082 L.atm/mol.K . T°

(2.5 atm . 8 L) / (3 mol . 0.082 L.atm/mol.K) = T°

T° = 81.3 K

We convert T° from K to C°

81.3K - 273 = -191.7°C

6 0
3 years ago
Read 2 more answers
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