The correct answer for the question that is being presented above is this one:
Given that:
delta Tb = Kbm Kb H2O = 0.52 degrees C/m
<span>delta Tf = Kfm Kf H2O = 1.86 degrees C/m
</span>
We need to know the formula for Molality.
molality = mol solute / kg solvent
<span>We are given the amount of solute in grams
Since amount of solute is given in moles, we have to convert 25 g NaCl to moles. Divide by molar mass. </span>
<span>25 g NaCl / 58.5 g/mol = 0.427 mol </span>
<span>Then, use the formula for molality. </span>
<span>molality = mol solute / kg solvent </span>
<span>= 0.427 / 1 </span>
<span>= 0.427 m </span>
<span>Use now the formula to get the boiling point.</span>
<span>delta Tb = Kbm </span>
<span>= (0.52)(0.427) </span>
<span>= 0.22C </span>
F = ma = (kg)(m/s2) = kg ´ m/s2 N
hope this helps :D
HEY THERE!!
For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1) .
This means that the angular quantum number for a principal quantum number of 2 is equivalent to:
l = 0 -> (n-1) = 0 -> (2-1) = 0 -> 1
So the answer is 0, 1
HOPE IT HELPED YOU.
