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Zarrin [17]
3 years ago
8

Explain and illustrate the notation for distinguishing between the different p orbitals in a sublevel.

Chemistry
1 answer:
masha68 [24]3 years ago
6 0

Here, the three different notation of the p-orbital in different sub-level have to generate

The value of azimuthal quantum number (l) for -p orbital is 1. We know that the magnetic quantum number m_{l} depends upon the value of l, which are -l to +l.

Thus for p-orbital the possible magnetic quantum numbers are- -1, 0, +1. So there will be three orbitals for p orbitals, which are designated as p_{x}, p_{y} and p_{z} in space.

The three p-orbital can be distinguish by the quantum numbers as-

For 2p orbitals (principal quantum number is 2)

1) n = 2, l = 1, m = -1

2) n = 2, l = 1, m = 0

3) n = 2, l = 1, m = +1

Thus the notation of different p-orbitals in the sub level are determined.  

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(c) ammonium carbonate + lead nitrate ? Step-by-step solution Step 1 of 3 v Step 2 of 3 v Step 3 of 3 ^ c) The ions formed in so
kenny6666 [7]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium carbonate and lead nitrate is given as:

(NH_4)_2CO_3(aq.)+Pb(NO_3)_2(aq.)\rightarrow PbCO_3(s)+2NH_4NO_3(aq.)

Ionic form of the above equation follows:

2NH_4^+(aq.)+CO_3^{2-}(aq.)+Pb^{2+}(aq.)+2NO_3^-(aq.)\rightarrow PbCO_3(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Pb^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow PbCO_3(s)

Hence, the net ionic equation is written above.

3 0
3 years ago
What is microorganisms
Wewaii [24]

Answer:

Technically a microorganism or microbe is an organism that is microscopic. The study of microorganisms is called microbiology. Microorganisms can be bacteria, fungi, archaea or protists. The term microorganisms does not include viruses and prions, which are generally classified as non-living.

4 0
2 years ago
1.Draw the skeletal structures of two different molecules that are each made of 5 carbon atoms and 12 hydrogen atoms then Name t
mihalych1998 [28]

Answer:

How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen atoms and 2 oxygen atoms

Explanation:

1.Draw the skeletal structures of two different molecules that are each made of 5 carbon atoms and 12 hydrogen atoms then Name the two molecules you drew.

7 0
3 years ago
Which of the following processes would you predict to have an increase in entropy?
Anna [14]
C. Melting ice. 
It is C because melting ice is a change of state from solid to liquid which requires an addition of energy(or entropy) into the system.
Condensation of water occurs from a gas to a liquid state, which takes energy out of the system(water) and gives it to the surroundings(air around it). Freezing water is the same as condensation except for the state change. Deposition is simply gas to a solid instantaneously so you can again see it as with the other two examples. 

6 0
3 years ago
A balloon contains 0.140 molmol of gas and has a volume of 2.78 LL . If an additional 0.152 molmol of gas is added to the balloo
levacccp [35]

Answer:

The final volume will be 5.80 L

Explanation:

Step 1: Data given

Number of moles gas = 0.140 moles

Volume of gas = 2.78 L

Number of moles added = 0.152 moles

Step 2: Calculate the final volume

V1/n1 = V2/n2

⇒ with V1 = the initial volume = 2.78 L

⇒ with n1 = the initial number of moles = 0.140 moles

⇒ with  V2 = The new volume = TO BE DETERMINED

⇒ with n2 = the new number of moles = 0.140 + 0.152 = 0.292 moles

2.78/0.140 = V2 /0.292

V2 = 5.80 L

The final volume will be 5.80 L

8 0
3 years ago
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