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Lana71 [14]
3 years ago
7

What is the formula for ammonium sulfate?

Chemistry
1 answer:
Lyrx [107]3 years ago
4 0
Ammonium Sulfate is represented as (NH4) 2SO4
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How to write 0.99966788 in scientific notation?
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Move the decimal 4 times to the right than thay number tomes 10^-4
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In which type of reaction do two lighter nuclei combine to form one heavier nucleus?
zvonat [6]

Answer:

Nuclear Fusion

Explanation:

<u>In nuclear fusion two lighter nuclei combine together in order to form one heavier nucleus.</u>

For example, the energy generated from the Sun is made by nuclear fusion: Two hydrogen (H, atomic number 1) nuclei combine in order to form one helium  (He, atomic number 2) nucleus.

<em>Nuclear fission is the opposite reaction</em>, in which one heavier nucleus splits into two lighter nuclei.

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PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP PLS PLS HELP ASAP THANKS
Alborosie

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2 years ago
Consider the following generic chemical equation: A + B → C + D Reactant A contains 85.1 J of chemical energy. Reactant B contai
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Answer:

Product D contains 30 J

Explanation:

We know energy does not destroy or create, it only transforms. So, at the right side of the equation we have the energy of the reactant A and the energy of the reactant B, as a sum, and, as a result we have to get the same energy plus the energy absorbed by the reaction.

So, we have,

Ea+Eb = Eabsorbed+Ec+Ed

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A chemistry student weighs out of chloroacetic acid into a volumetric flask and dilutes to the mark with distilled water. He pla
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Answer:

11.6mL of the 0.1400M NaOH solution

Explanation:

<em>0.154g of chloroacetic acid diluted to 250mL. Titrated wit 0.1400M NaOH solution.</em>

<em />

The reaction of chloroacetic acid, ClCH₂COOH (Molar mass: 94.5g/mol) with NaOH is:

ClCH₂COOH + NaOH → ClCH₂COO⁻ + Na⁺ + H₂O

<em>Where 1 mole of the acid reacts per mole of the base.</em>

<em />

That means the student will reach equivalence point when moles of chloroacetic acid = moles NaOH.

You will titrate the 0.154g of ClCH₂COOH. In moles (Using molar mass) are:

0.154g ₓ (1mol / 94.5g) = <em>1.63x10⁻³ moles of ClCH₂COOH</em>

To reach equivalence point, the student must add 1.63x10⁻³ moles of NaOH. These moles comes from:

1.63x10⁻³ moles of NaOH ₓ (1L / 0.1400moles NaOH) = 0.0116L of the 0.1400M NaOH =

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