What is the formula for ammonium sulfate?

Chemistry

1 answer:

Lyrx [107]4 years ago

4 0

Ammonium Sulfate is represented as (NH4) 2SO4

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A graph of gas pressure versus the number of particles in a container is a straight line. Which other relationship will have a s

Elanso [62]

Volume has the same relationship with the number of particles than the pressure.

You can see it in the ideal gas equation: PV = nRT

As much as V and P are proportional to n.

3 0

4 years ago

For the following reaction, identify the substances being oxidized and reduced (including their oxidation numbers), the oxidizin

V125BC [204]

<span>Si is reduced/Oxidizing reagent Mg is oxidized/reducing reagent</span>

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3 years ago

Unlike gases, the behavior of liquids and solids cannot be described by a set of laws that can be applied regardless of the iden

Tresset [83]

Answer:

a. True

Explanation:

The gases that we study are governed by different laws of physics. Gases behaves according to some given set of laws like the Universal gas laws, Boyles law, Charles law, Gay Lussac's law and many more.

But we do not see a definite pattern or rule when we study solids or liquids. The behavior of the solids and liquids are not described by the set of laws which are applied regardless of the identity of the substance.

6 0

3 years ago

What defines the mass number of an isotope

vekshin1

The mass number of an isotope is determined by the number of neutrons in the isotope plus the number of protons.
For instance Carbon-13 is an isotope of carbon. The "13" is the mass number of the isotope.
So, in this example, 13 = #protons + #neutrons

8 0

4 years ago

A sample of argon gas at stp occupies 56.2 liters. determine the number of moles of argon and the mass in the sample. for the ab

andreev551 [17]

We can use the ideal gas law equation to find the number of moles;
PV = nRT
where P - pressure
V - volume - 56.2 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature
standard temperature is 273 K
and standard pressure - 101 325 Pa
we can rearrange the equation to find the number of moles
$n = \frac{PV}{RT}$
substituting the values in the equation
$n = \frac{101325Pa*56.2 x 10⁻³ m³}{8.314 Jmol⁻¹K⁻¹*273K}$
n = 2.51 mol
molar mass of Ar - 40 g/mol
mass of Ar in the sample - 2.51 mol x 40 g/mol = 100.4 g

7 0

4 years ago