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3 years ago

When it is summer at the South Pole,

1 answer:

6 0

D

The northern hemisphere is experiencing winter because it is tilted away from the sun whereas the south experiences summer because it is tilted towards the sun

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while performing a sonogram, to minimize risk to the fetus, which imaging mode trade off would be most appiclable.

Alexus [3.1K]

Answer: Use M-mode instead of pulse-wave Doppler to measure the fetal heart rate.

Explanation: M-mode is a famous ultrasound process during the early days of Ultrasound technologies, M-mode has a very high sampling rate. One of the major disadvantages is that it may be difficult to align the M-mode to be the perpendicular to the SEPTUM. M-mode has only one (1) dimensional view of an object,to minimize the risk to the Fetus, M-mode is the most applicable tradeoff. Specifically, M-mode is mainly used because of its Axial and temporal resolution of the structure of objects.

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4 years ago

In the ballistic pendulum experiment (A.K.A conservation of momentum & energy), the velocity of the projectile was measured

Fed [463]

Answer: The combined velocity = 0.413m/a

Maximum angle Ø = 54.7

Explanation: Please find the attached files for the solution

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3 years ago

What is the until of measure for speed?

Vitek1552 [10]

Answer:

the unit is m/s

Explanation:

Speed has the dimensions of distance divided by time. The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour

5 0

4 years ago

How would the speed of Earth's orbit around the sun change if Earth's distance from the sun

gayaneshka [121]

If Earth’s distance from the sun increased by 4 times then the speed of Earth’s orbit around the sun would decrease by a factor of 2.

Answer: Option 3

<u>Explanation:</u>

From Newton’s second law of motion, it is known that any kind of external force acting on an object will be equal to object’s mass and acceleration exerted on the object. So in this case, the gravitational force between Earth and Sun will be equal to the mass (M) and acceleration exerted on Earth.

$\text {Gravitational force}=\text {M} \times \text {Acceleration of Earth around the orbit}$

It is known that,

$\text {Acceleration in orbital motion}=\frac{\left(\text {velocity at which the Earth rotates)}^{2}\right.}{\text { Distance of Earth from the Sun}}$

Thus, substituting this, we get,

$\text {Gravitational force}=\frac{\text {M} \times\left(\text {velocity at which the Earth rotates)}^{2}\right.}{\text { Distance of Earth from the sun}}$

Also, we know,

$\text {Gravitational force}=\frac{G \times M \text { of sun } \times \text {M of Earth}}{(\text {Distance of Earth from the Sun})^{2}}$

Then, comparing both the equation, we get the orbital velocity as,

$\text { Orbital velocity } v=\sqrt{\frac{G \times M \text { of Sun }}{\text { Distance of Earth from the Sun }}}=\sqrt{\frac{G M}{r}}$

So, here G is gravitational constant, M is the mass of Sun and r is the distance of separation of Earth from Sun.

If the distance of Earth from Sun increases by 4 times so r’ will be 4r. Thus the new orbital velocity v’ will be

$v^{\prime}=\sqrt{\frac{G M}{r^{\prime}}}=\sqrt{\frac{G M}{4 r}}=\frac{1}{2} \sqrt{\frac{G M}{r}}$

So,

$v^{\prime}=\frac{1}{2} v$

Thus, the orbital speed will be decreased by a factor of 2 when the distance of Earth from the Sun increased by 4 times.

7 0

3 years ago

Question:The greater the

Romashka-Z-Leto [24]

Answer:

True

Explanation:

when the object is larger , the inertia of the object is larger so its tendency to change its state of motion is reduced is reduced.

5 0

3 years ago