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Lerok [7]
3 years ago
11

If the speed of light in a sphere is 2 × 108 m/s, its index of refraction is

Physics
1 answer:
yuradex [85]3 years ago
7 0
Refractive index, n = v1/v2

Where,
v1 = Speed of light in vacuum = 3*10^8 m/s
v2 = Speed of light in a medium (sphere) = 2*10^8 m/s

Therefore,
n= (3*10*8)/(2*10^8) = 1.5
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(Plzzzz help!!!) (50 points!!!)
stellarik [79]

Answer:

Write the following Quantitiesin scientific notation.

a. 10130 Pa to 2 decimal place

b. 978.15m * s-2 to one decimal place

c 0.000001256 A to3 decimal place​

Add your answer and earn points.

Answer

5.0/5

2

kobenhavn

Expert

5.5K answers

43M people helped

Answer: a.

b.  

c.  

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as

a. 10130 Pa to 2 decimal place is written as

b.  to 1 decimal place is written as

c.   to 3 decimal places is written as

Explanation:

4 0
2 years ago
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What type of image can a convex mirror produce?
user100 [1]

It must be a virtual image, because this is the only kind of image it can produce.

4 0
3 years ago
Give a example of scalar quantity
Serhud [2]

speed, volume, mass, temperature and power

7 0
3 years ago
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1.The distance moved by objects in a given interval of time can help us to decide which one is faster or slower. Do you agree wi
shutvik [7]

Answer:

The rate of change of distance is defined as speed.

Explanation:

The speed is defined as the rate of change of distance.

Speed = distance/ time

When we know the distance and the time, we get the value of speed. So, e know that who is moving fast or slow.

hen a graph is pltted beteen the distance and time, the slope of the graph gives the value of speed. So, by checking the slopes, hoseslope ismore, the speed is more and thusit is moving faster.

So, i agree with the statement.  

6 0
3 years ago
Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plate
Daniel [21]

Solution:

The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :

$E=\frac{V}{D}$

Differentiating on both the sides with respect to time, we get

$\frac{dE}{dt}=\frac{1}{D}\frac{dV}{dt}$

Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :

$\frac{dE}{dt}=\frac{1}{D}\frac{dV}{dt}$

      $=\frac{1}{1.4 \times 10^{-3}} \times 110$

      $=7.85 \times 10^4$  V/m-s

8 0
3 years ago
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