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jeka94
3 years ago
14

Which statement about solubility is true?

Physics
1 answer:
NISA [10]3 years ago
7 0
Answer to your question is B. I did a science lab over this...
Test was to see which would dissolve fastest... A tablet in warm water... and a tablet in cold water....

And this question isn't asking for solids or gasses.... because something dissolves with a liquid :P thanks...
You might be interested in
You compress a spring by a distance of 0.2 m. The spring has a spring constant of 37 N/m. When you release the spring, it snaps
Serggg [28]
At that point it is no longer trying to uncompress nor is it trying to stretch.  This is the same thing as a pendulum at the bottom of its swing, no longer falling but not yet rising against gravity.  Thus the kinetic energy there is the same as the potential energy when it is compressed.  The energy of compression is
\frac{1}{2}k x^{2}
This gives E=0.5(37)(0.2)²=0.74J
This is the same as the kinetic energy when it is at natural length
7 0
3 years ago
Read 2 more answers
Note: the 2 in the answers are exponents
stiks02 [169]

Final speed after collision with the wall

v_f = -0.4 m/s

before collision the speed of ball initially

v_i = 0.6 m/s

time taken for the collision

\Delta t = 0.2 s

now as per the formula of acceleration we know that

a = \frac{v_f - v_i}{\Delta t}

now plug in all values in it

a = \frac{-0.4 - 0.6}{0.2}

a = -5.0 m/s^2

so acceleration is - 5 m/s/s for above situation

4 0
4 years ago
If someone is driving 100 miles in 60 minutes then drives 150 miles in 100 minutes west, what is his acceleration rate.
Sliva [168]

Answer:

his acceleration rate is -0.00186 m/s²

Explanation:

Given;

initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)

time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s

final position of the car, x₁ = 150 miles = 241,350 m

time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s

The initial velocity is calculated as;

u = 160, 900 m / 3,600 s

u = 44.694 m/s

The final velocity is calculated as;

v = 241,350 m / 6,000 s

v = 40.225 m/s

The acceleration is calculated as;

a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225  - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\

Therefore, his acceleration rate is -0.00186 m/s²

6 0
3 years ago
A boy weighs 40 kilograms. He runs at a velocity of 4 meters per second north. Which is his momentum?
Bogdan [553]
The boy's momentum is 160 kg*m/s north.

The formula of momentum is p = mv, where p is momentum.
p = 40 kg * 4m/s north
p =160 kg*m/s north

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>


4 0
3 years ago
Read 2 more answers
Given that:<br><br> = 2i + 9j ; and ⃗ = -i – 4j . Find . ⃗ ​
Marat540 [252]

Answer:

A.B = -38

Explanation:

A = 2i + 9j and B = -i - 4j.

So, A.B = (2i + 9j).(-i - 4j)

= 2i.(-i) + 2i.(-4j) + 9j.(-i) + 9j.(-4j)

= -2i.i - 8i.j - 9j.i - 36j.j

since i.i = 1, j.j = 1, i.j = 0 and j.i = 0, we have

A.B = -2(1) - 8(0) - 9(0) - 36(1)

A.B = -2 - 0 - 0 - 36

A.B = -38

5 0
3 years ago
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