1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pogonyaev
3 years ago
13

In Ptolemy's Earth-centered model for the solar system, Venus's phase is never full as viewed from Earth because it always lies

between Earth and the Sun. In reality, as Galileo first recognized, Venus is __________.
Physics
1 answer:
tiny-mole [99]3 years ago
7 0
<h2>Answer: in full phase</h2>

Explanation:

Galileo observed that Venus presented phases (such as those of the moon) together with a variation in size; observations that are only compatible with the fact that <u>Venus rotates around the Sun and not around Earth.  </u>

This is because Venus presented <u>its smaller size when it was in full phase and the largest size when it was in the new one</u>, when it is between the Sun and the Earth.  

In other words: When Venus is in its full phase it is not possible to observe it from the Earth because always in this phase, Venus, the Sun and the Earth are in conjunction (or aligned).  This means <u>the Sun is between Venus and Earth</u>, in the orbit that both planets describe around this star.

Therefore, from the Earth, the Sun covers Venus.

This fact along with other discoveries were presented by Galileo to the Catholic Church (which supported the geocentric theory at that time) as a proof that completely refuted Ptolemy's geocentric system and affirmed Copernicus' heliocentric theory.

You might be interested in
Assuming 100% efficient energy conversion, how much water stored behind a 50 centimetre high hydroelectric dam would be required
11Alexandr11 [23.1K]

Complete question is;

Assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery with power rating, 12 V, 50 Ampere-minutes

Answer:

Amount of water required to charge the battery = 7.35 m³

Explanation:

The formula for Potential energy of the water at that height = mgh

Where;

m = mass of the water

g = acceleration due to gravity = 9.8 m/s²

H = height of water = 50 cm = 0.5 m

We know that in density, m = ρV

Where;

ρ = density of water = 1000 kg/m³

V = volume of water

So, potential energy is now given as;

Potential energy = ρVgH = 1000 × V × 9.8 × 0.5 = (4900V) J

Now, formula for energy of the battery is given as;

E = qV

We are given;

q = 50 A.min = 50 × 60 = 3,000 C

V = 12 V

Thus;

qV = 3,000 × 12 = 36,000 J

E = 36,000 J

At a 100% conversion rate, the energy of the water totally powers the battery.

Thus;

(4900V) = (36,000)

4900V = 36,000

V = 36,000/4900

V = 7.35 m³

5 0
3 years ago
A runner whose mass is 54 kg accelerates from a stop to a speed of 7 m/s in 3 seconds. (A good sprinter can run 100 meters in ab
Darya [45]

Answer:

a. F=126N

b. E_K=1323J

Explanation:

Given:

m=54kg

v=7 m/s

t= 3s

The runner force average to find given the equations

a.

F=m*a

a=\frac{v}{t}

F=m*\frac{v}{t}=54kg*\frac{7m/s}{3s}

F=126N

b.

Work done by the system by this force so

W=F*d

W=E_K

E_K=\frac{1}{2}*m*v^2

E_K=\frac{1}{2}*54kg*(7m/s)^2

E_K=1323J

6 0
3 years ago
Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the end
yawa3891 [41]

Correct question:

Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?

a. from the bottom of a hill to the top

b. on a circular nature trail

c. on a sidewalk from his house to the mall

d. from the beginning of a straight track to the end

Answer:

b. on a circular nature trail

Explanation:

As it is mentioned that Manny that his reference point from where she started is same as ending point meaning that she moved in a circular path making point B correct answer.

7 0
3 years ago
Read 2 more answers
Q7) A box sliding with a velocity of 5 m/s accelerates at 2 m/s^2. How
grigory [225]

Answer:

The box displacement after 6 seconds is 66 meters.

Explanation:

Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (\Delta s), in meters, can be determined by the following expression:

\Delta s = v_{o}\cdot t+\frac{1}{2}\cdot a\cdot t^{2} (1)

Where:

v_{o} - Initial velocity, in meters per second.

t - Time, in seconds.

a - Acceleration, in meters per square second.

If we know that v_{o} = 5\,\frac{m}{s}, t = 6\,s and a = 2\,\frac{m}{s^{2}}, then the box displacement after 6 seconds is:

\Delta s = 66\,m

The box displacement after 6 seconds is 66 meters.

5 0
3 years ago
The thread around a screw is a lever.
monitta
It's a plain, not a lever
7 0
4 years ago
Other questions:
  • What will the pressure inside the container become if the piston is moved to the 1.20 l mark while the temperature of the gas is
    5·1 answer
  • is it possible for the gravitational force between two 50-kg objects to be less than the gravitational force between a 59-kg obj
    13·1 answer
  • If it takes 50n of force to lift a 450n what is the ma of the machine
    5·1 answer
  • You drive in a straight line at 22 m/s for 12 miles, then at 30 m/s for another 12 miles. (a) How does your average speed sav co
    14·1 answer
  • To push a 25.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel
    7·1 answer
  • WILL AWARD OVER 50 POINTS TO WHOEVER ANSWERS FIRST
    8·1 answer
  • If a dog has a mass of 2.5 kg, what is its weight and what is the normal force that it feels.<br> I
    14·1 answer
  • Help please!! Physics grade 8​
    13·1 answer
  • Testing shows that a sample of wood from an artifact contains 12.5% of the original amount of carbon-14. Given that the half-lif
    14·2 answers
  • In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!