Question

In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m/s^2 . Ignore air resistance. A flea jumps straight up to a maximum height of 0.490 m. What is its initial velocity v0 as it leaves the ground?

Answer 1

The initial velocity used by the flea to jump straight upward is 3.1 m/s

Data obtained from the question

The following data were obtained from the question:

• Acceleration due to gravity (g) = 9.8 m/s²
• Maximum height (h) = 0.49 m
• Final velocity (v) = 0 m/s (at maximum height)
• Initial velocity (u) =?

How to determine the initial velocity

The initial velocity used by the flea to jump upward can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – (2 × 9.8 × 0.49)

0 = u² – 9.604

Collect like terms

u² = 0 + 9.604

u² = 9.604

Take the square root of both sides

u = √9.604

u = 3.1 m/s

Thus, the initial velocity is 3.1 m/s

Learn more about motion under gravity:

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