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Hunter-Best [27]
2 years ago
14

Testing shows that a sample of wood from an artifact contains 12.5% of the original amount of carbon-14. Given that the half-lif

e of carbon-14 is 5730 years, how old is the artifact?
A. 22,920 years
B. 17,190 years
C. 11,460 years
D. 5730 years
Physics
2 answers:
castortr0y [4]2 years ago
7 0

Answer: i think

Explanation:

d

ratelena [41]2 years ago
5 0

Answer:

B. 17,190 (A P E X)

Explanation:

If the half-life of carbon-14 is 5730 years then for every 5730 years the original amount of the carbon-14 is cut in half. So if it originally started at 100% when it was new then in 5730 years it would drop to 50%. After that, every 5730 years it drops to 25% and then 12.5% and so on.

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A cube of water 10 cm on a side is placed in a microwave beam having Ea = 11 kV/m‘ The microwaves illuminate one faceofthe cube,
Shtirlitz [24]

Answer:

The time is 133.5 sec.

Explanation:

Given that,

One side of cube = 10 cm

Intensity of electric field = 11 kV/m

Suppose How long will it take to raise the water temperature by 41°C Assume that the water has no heat loss during this time.

We need to calculate the rate of energy transfer from the beam to the cube

Using formula of rate of energy

P=(0.80)IA

P=0.80\times\dfrac{c\mu_{0}E^2}{2}\times A

Put the value into the formula

P=0.80\times\dfrac{3\times10^{8}\times8.85\times10^{-12}\times(1.1\times10^{4})^2}{2}\times(10\times10^{-2})^2

P=1285.02\ W

We need to calculate the amount of heat

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E=1000\times(0.10)^3\times4186\times41

E=171626\ J

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t=\dfrac{E}{P}

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t=\dfrac{171626}{1285.02}

t=133.5\ sec

Hence, The time is 133.5 sec.

3 0
3 years ago
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Svetllana [295]

Answer: i can see properly

Explanation:

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2 years ago
Water enters a cylindrical tank through two pipes at rates of 250 and 100 gal/min. If the level of the water in the tank remains
tester [92]

Answer:

The total amount of water that enters the tank is:

250 gal/min + 100 gal/min = 350gal/min.

Then, if the level of the water remains constant, this means that the water leaves the tank at a rate of 350gal/min.

We know that the diameter of the pipe is 8 inches, then the area of the pipe is:

A = pi*(d/2)^2 = 3.14*(4in)^2 = 50.24in^2

now, the flow can be calculated as:

Q = v*A = (velocity*area)

if we want to write our velocity in inches per minute, then we need to write the entering flow in cubic inches:

1 gallon = 231 in^3

then:

350gal/min = (350*231) in^3/min = 80,850 in^3/min.

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Q = 80,850 in^3/min. = v*A = v*50.24in^2

v =  (80,850in^3/min)/50.24in^2 = 1609.3 in/min.

The velocity of the flow leaving the tank is 1609.3 in/min.

3 0
3 years ago
If there is no oxygen in outer space, and, at the same time, oxygen must be present for fire, where does the sun come from?​
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3 0
3 years ago
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Un movil de masa 12Kg sobre el cual estan actuando varias fuerzas F_1=48N, F_2=60N y F_3=30N Calcular la aceleracion con la cual
Nikitich [7]

Answer:

Lamentablemente el problema está incompleto, pues no sabemos la dirección en la que se aplican las fuerzas. Por ello, voy a resolver el problema asumiendo dos casos. (abajo se puede ver una imagen donde se describe cada caso)

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Entonces la fuerza neta será la suma de las 3 fuerzas, entonces:

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Y por la segunda ley de Newton sabemos que:

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fuerza igual a masa por aceleración.

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En este caso, la aceleración será:

a = 42N/12kg = 3.5 m/s^2

7 0
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