Question

Please helpppppppppp

Answer 1

The stone lands 133 m far from the bottom of the cliff

Explanation:

The motion of the stone in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by considering the vertical motion: since it is a free fall motion, we can use the suvat equation

$s=ut+\frac{1}{2}at^2$

where

s = 85 m is the vertical displacement, the height of the cliff (we chose downward as positive direction)

u = 0 is the initial vertical velocity of the stone

t is the time  the stone takes to reach the ground

$a=g=9.8 m/s^2$ is the acceleration of gravity

Solving for t, we find the time:

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(85)}{9.8}}=4.16 s$

Now we can consider the horizontal motion, which is a uniform motion at constant speed. The horizontal distance travelled is given by :

$d=v_x t$

where  we know:

$v_x = 32 m/s$ is the horizontal velocity, which is constant

t = 4.16 s is the time of flight

Solving for d, we find:

$d=(32)(4.16)=133 m$

So, the stone lands 133 m far from the base of the cliff.

Learn more about projectile motion here:

brainly.com/question/8751410

#LearnwithBrainly