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3 years ago

If five joules were required to move a crate in 3.7 seconds, what power was applied?

Physics

1 answer:

AleksAgata [21]3 years ago

8 0

Answer:

The answer to your question is 1.35 Watts

Explanation:

Data

Work = W = 5 J

time = t = 3.7 s

Power = P = ?

Formula

Power is a rate in which work is done or energy is transferred over time

P = $\frac{W}{t}$

Substitution

$P = \frac{5}{3.7}$

Result

P = 1.35 W

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