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aalyn [17]
3 years ago
8

If five joules were required to move a crate in 3.7 seconds, what power was applied?

Physics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

The answer to your question is 1.35 Watts

Explanation:

Data

Work = W = 5 J

time = t = 3.7 s

Power = P = ?

Formula

Power is a rate in which work is done or energy is transferred over time

P = \frac{W}{t}

Substitution

P = \frac{5}{3.7}

Result

P = 1.35 W

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Explanation:

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In order to perform this operation, we have to:

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In this problem, the original vector has a lenght of 8.6 m and it points in the negative x direction. Now we have to find the vector -3.7A, so we have:

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So the final vector is 31.8 m in the positive x-direction, and therefore its x-component is also 31.8 m in the positive direction.

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