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aalyn [17]
3 years ago
8

If five joules were required to move a crate in 3.7 seconds, what power was applied?

Physics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

The answer to your question is 1.35 Watts

Explanation:

Data

Work = W = 5 J

time = t = 3.7 s

Power = P = ?

Formula

Power is a rate in which work is done or energy is transferred over time

P = \frac{W}{t}

Substitution

P = \frac{5}{3.7}

Result

P = 1.35 W

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What term refers to the product of an object’s mass and velocity
labwork [276]

Answer:Momentum

Explanation:

Product of an object mass and velocity is called Momentum. Basically momentum is the measure of mass in motion . More is the mass more will be the momentum and similar applies for velocity.

For example a bus moving with low velocity can have a same momentum as that of a bullet moving with a very high velocity

Momentum is denoted by Symbol P

\vec{P}=m\vec{v}

   

6 0
3 years ago
Calculate the air pressure in the pressurized tank, if h1 = 0. 18 m, h2 = 0. 2m and h3 = 0. 25m. The density of the mercury, wat
fomenos

The air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

<h3 /><h3>What is pressure?</h3>

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

Pressure is found as the product of the density,acceleraton due to gravity and the height.

P₁=ρ₁gh₁

P₁=13,600 kg/m³×9.81 (m/s²)×0.18 m

P₁=24014.88 N/m²

P₂=ρ₂gh₂

P₂= 1000 kg/m³×9.81 (m/s²)×00.2 m

P₂=196.2 N/m²

P₃=ρ₃gh₃

P₃=850 kg/m³×9.81 (m/s²)×0.25

P₃=2084.625  N/m²

Hence,the air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

To learn more about the pressure refer to the link;

brainly.com/question/356585

#SPJ4

6 0
2 years ago
Was Copernicus heliocentric or geocentric
Anuta_ua [19.1K]
Copernicus preferred the heliocentric model.
8 0
4 years ago
Read 2 more answers
Newton's third law of motion involves:
madreJ [45]

Answer:

B

Explanation:

There are a pair of forces acting on the 2 interacting objects

You're welcome <3

8 0
3 years ago
a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?
Liono4ka [1.6K]

<u>Answer:</u>

The acceleration of the car is 3.13 m/s^2

<u>Explanation:</u>

In the question it is given that car initially heads north with a velocity 15 m/s. It then accelerates for 4.25 s and in the end its velocity is 28.3 m/s.

initial velocity u = 15 m/s

time t=4.25 s

final velocity v=28.3 m/s

The equation of acceleration is

a= \frac{(v-u)}{t}

= \frac{(28.3-15)}{4.25} =  \frac {13.3}{4.25} =3.13m/s^2

The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.

7 0
3 years ago
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