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aalyn [17]
3 years ago
8

If five joules were required to move a crate in 3.7 seconds, what power was applied?

Physics
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

The answer to your question is 1.35 Watts

Explanation:

Data

Work = W = 5 J

time = t = 3.7 s

Power = P = ?

Formula

Power is a rate in which work is done or energy is transferred over time

P = \frac{W}{t}

Substitution

P = \frac{5}{3.7}

Result

P = 1.35 W

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4 km/hr

Explanation:

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3 years ago
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Here, the linear momentum is conserved

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3 years ago
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