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Vlada [557]
3 years ago
15

A large crate of mass m is placed on the back of a truck but not tied down. As the truck accelerates forward with an acceleratio

n a, the crate remains at rest relative to the truck. What force causes the crate to accelerate forward?
a) normal force
b) force of gravity
c) force of friction between the crate and the floor of the truck
d) the "ma" force
e) none of these
Physics
2 answers:
Margaret [11]3 years ago
5 0

Answer: Option C

Explanation: Let's analyze each possible force:

A)normal force, it pushes in the direction in which the box has contact with some surface, in this case, is in the bottom of the truck, so this force pushes upwards.

B) Force of gravity always pushes downwards, so it can not accelerate the box in the same direction in which the truck is moving.

c) The force of friction points in the opposite direction in which the box would move, if the truck moves to the right, the box will move to the left, so the friction pushes also to the right, which is the same direction in which the truck is moving.

D) there is nothing called the "ma" force.

Now, the correct option would be C; the force of friction (the statical one, because we know that the box does not move)

Andrew [12]3 years ago
4 0
"Force of friction between the crate and the floor of the truck" is the one force among the choices given in the question that <span>causes the crate to accelerate forward. The correct option among all the options that are given in the question is the third option or option "c". I hope the answer helps you.</span>
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3 years ago
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3 An empty hot tub has a mass of 320 kg. When filled, the tub holds 600 gallons of water (rho = 62.4 lbm/ft3). The local acceler
ehidna [41]

Answer:

Total weight of the hot tub and water is 5676.6 pounds-force

Explanation:

rho = 62.4lbm/ft^3 × 1ft^3/7.481gal = 8.34lbm/gal

Mass of water = rho × volume = 8.34lbm/gal × 600 gallons = 5004lbm = 5004×0.45359kg = 2269.8kg

Total mass of hot tub and water = 320kg + 2269.8kg = 2589.8kg

Local acceleration due to gravity = 32ft/s^2 = 32ft/s^2 × 1m/3.2808ft = 9.75m/s^2

Total weight of hot tub and water = 2589.8kg × 9.75m/s^2 = 25250.55N = 25250.55/4.4482 lbf = 5676.6 lbf

6 0
3 years ago
A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
Jet001 [13]
<h2>The impact is occurred at a distance 348.55 m far from person.</h2>

Explanation:

Let s be the distance to the impact position and t be the time when he hears the sound though concrete after impact.

Time when he hears impact through air = t + 0.90

The distance traveled by sound wave in both concrete and air is s.

Speed of sound in air = 343 m/s

Speed of sound in concrete = 3000 m/s

Distance traveled in air = Distance traveled in concrete

343 x Time when he hears impact through air = 3000 x Time when he hears impact through concrete

        343 x (t + 0.90) = 3000 x t

                  3000t - 343 t = 343 x 0.90

                  2657t = 308.7

                      t = 0.116 s

Distance traveled in concrete = 3000 x t = 3000 x 0.116 = 348.55m

So the impact is occurred at a distance 348.55 m far from person.

4 0
3 years ago
How large must the coeffficient of static friction be between the tires and the road if a car is to round a level curve of radiu
m_a_m_a [10]

Answer:

Coefficient of static friction required = 0.94

Explanation:

Coefficient of static friction required =\frac{v^2}{gR}

Velocity, v = 120 km/h = 33.33 m/s

g = 9.81 m/s²

R = 120 m

Coefficient of static friction required=\frac{33.33^2}{9.81\times 120}=0.94

Coefficient of static friction required = 0.94

5 0
3 years ago
A car with a mass of 880 kg is moving on the road with constant velocity. The force exerted by engine is 1600N. What is the fric
vovangra [49]

Answer:

1600 N

Explanation:

F-F' = ma.................. Equation 1

Where F = Force exerted by the engine, F' = Frictional Force, m = mass of the car, a = acceleration of the car.

make F' the subject of the equation

F' = F-ma............... Equation 2

Given: F = 1600 N, m = 880 kg, a = 0 m/s (moving with a constant velocity).

Substitite these values into equation 2

F' = 1600+880(0)

F' = 1600 N.

4 0
2 years ago
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