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gulaghasi [49]
3 years ago
15

calculate the resistance of 50m length of wire of cross sectional area 0.01 square mm and of resistivity 5*10 to the power minus

8
Physics
1 answer:
Pachacha [2.7K]3 years ago
8 0
Resistance R = resistivity * length / area

R = 5  10^{-8} * 50 m / 0.01 *  10^{-3} * 10^{-3}

R =  250 Ohms

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An electric motor does 900j of work for 8 hours. Calculate the power used​
nataly862011 [7]

Answer:

0.031 W

Explanation:

The power used is equal to the rate of work done:

P=\frac{W}{t}

where

P is the power

W is the work done

t is the time taken to do the work W

In this problem, we have:

W = 900 J is the work done by the motor

t = 8 h is the time taken

We have to convert the time into SI units; keeping in mind that

1 hour = 3600 s

We have

t=8\cdot 3600 =28,800 s

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6 0
3 years ago
A hydrogen discharge lamp emits light with two prominent wavelengths: 656 nm (red) and 486 nm (blue). The light enters a flint-g
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Answer:

The angle between the red and blue light is 1.7°.

Explanation:

Given that,

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Wavelength of blue = 486 nm

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Suppose we need to find the angle between the red and blue light as it leaves the prism

n_{r}=1.572

n_{b}=1.587

We need to calculate the angle for red wavelength

Using Snell's law,

n_{r}\sin\theta_{i}=n_{a}\sin\theta_{r}

Put the value into the formula

1.572\sin37=1\times\sin\theta_{r}

\theta_{r}=\sin^{-1}(\dfrac{1.572\sin37}{1})

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We need to calculate the angle for blue wavelength

Using Snell's law,

n_{b}\sin\theta_{i}=n_{a}\sin\theta_{b}

Put the value into the formula

1.587\sin37=1\times\sin\theta_{b}

\theta_{b}=\sin^{-1}(\dfrac{1.587\sin37}{1})

\theta_{b}=72.7^{\circ}

We need to calculate the angle between the red and blue light

Using formula of angle

\Delta \theta=\theta_{b}-\theta_{r}

Put the value into the formula

\Delta \theta=72.7-71.0

\Delta \theta=1.7^{\circ}

Hence, The angle between the red and blue light is 1.7°.

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3 years ago
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