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Allisa [31]
1 year ago
11

A certain gas is found in the exhaust of automobiles and power plants. Consider a 1.53 L sample of a gas at a pressure of 5.6 x

10' Pa. If the pressure is changed to 1.5 × 10 Pa at a constant temperature, what will be the new volume of the gas?​
Chemistry
1 answer:
Olegator [25]1 year ago
6 0

The new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L. Details about volume of the gas can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the Boyle's law equation as follows:

P1V1 = P2V2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • V1 = initial volume
  • V2 = final volume

1.53 × 5.6 × 10⁵ = 1.5 × 10⁵ × V2

8.568 × 10⁵ = 1.5 × 10⁵V2

V2 = 8.57 × 10⁵ ÷ 1.5 × 10⁵

V2 = 5.7L

Therefore, the new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L.

Learn more about volume at: brainly.com/question/12357202

#SPJ1

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A solution with a pH of 6.52 has a hydronium ion concentration of 3.02x10-7 mol/L and a hydroxide ion concentration of 3.31x10-8 mol/L.

The hydronium ion concentration of a solution can be calculated from pH by using 10^{-pH}. For a pH of 6.52, hydronium ion concentration is 3.02x10-7 mol/L.

The concentration of hydroxide ions can be determined by identifying the value of pOH. The sum of pOH and pH is equal to 14, which is based on the negative logarithm of the ion-product constant of water. At a pH of 6.52, pOH is equal to 7.48.

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3 0
1 year ago
State which of the following set of quantum number would be possible and which would be permissible for an electron in an atom.
raketka [301]

Answer:

The correct option is: e) n=4, l=3, m_{l} = - 2 , m_{s} = - 1/2                                              

Explanation:

The four quantum numbers that describe the electrons in an atom are: The principal: n, azimuthal: l, magnetic: m, and  spin: s.

For a given electron, the values of the quantum numbers should be in the <u>given range</u>- principal quantum number: n ≥ 1;

azimuthal quantum number: 0 ≤ l ≤ n − 1;

magnetic quantum number: −l ≤ m_{l} ≤ +l;

spin quantum number: −s ≤ m_{s} ≤ +s

Now, for n= 4,

The value of l: 0 to n − 1 =  0 to 3 = 0, 1, 2, 3

The value of m_{l} for l= 3 : -3 to +3 = -3, -2, -1, 0, +1, +2, +3

The value of m_{s}: -1/2, +1/2

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