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9966 [12]
3 years ago
8

slader A baseball player slides to a stop on level ground. Using energy consideration, calculate the distance the 65 kg baseball

player slides, given his initial speed is 6 m/s and the force of friction against him is a constant 450N.
Physics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

2.6 m

Explanation:

From work energy theorem we deduce that

0.5mv^{2}=fd

The kinetic energy equals to the work dine against friction energy.

Where m represent mass, v is the velocity, f is the frictional force and d is unknown distance that the player slides.

Making d the subject of the formula then d=\frac {mv^{2}}{2f}

Then by substituting 450N for f, 65 kg for m and 6 m/s for v we obtain

d=\frac {65*6^{2}}{2*450}=2.6m

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Two 20kg spheres are placed with their
Maslowich

Answer:

F = 1.07 x 10⁻⁷ N

Explanation:

The gravitational force of attraction between two objects can be found by the use of Newton's Gravitational Law:

F = \frac{Gm_{1}m_{2}}{r^2}\\\\

where,

F = Gravitational Force of attraction = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of spheres = 20 kg

r = distance between the objects = 50 cm = 0.5 m

Therefore,

F = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(20\ kg)(20\ kg)}{(0.5\ m)^2}\\\\

<u>F = 1.07 x 10⁻⁷ N</u>

5 0
3 years ago
acontainer is filled whith mercury to alevel of 10m whit water to alevel of 8m and whit oil to alevel of 5m the densities oil ,w
Alborosie

Answer:

1450.4 KNm^{2}

Explanation:

Pressure = ρhg

where: ρ is the density of the liquid, h is the height and g the force of gravity.

Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury

So that,

i. Pressure of oil = ρhg

(ρ = 0.8 g/cm³ = 800 kg/m³)

                        = 800 x 5 x 9.8

                        = 39200

Pressure of oil = 39200 Nm^{2}

ii. Pressure of water = ρhg

(ρ = 1 g/cm³ = 1000 kg/m³)

                                      = 1000 x 8 x 9.8

                                     = 78400

Pressure of water = 78400 Nm^{2}

ii. Pressure of mercury = ρhg

(ρ = 13.6 g/cm³ = 13600 kg/m³)

                      = 13600 x 10 x 9.8

                      = 1332800

Pressure of mercury = 1332800 Nm^{2}

So that,

Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800

                                               = 1450400

                                               = 1450.4 KNm^{2}

Total pressure exerted by the liquids at the base is 1450.4 KNm^{2}.

8 0
3 years ago
Mario golpea el balón con el pie para lanzárselo a Tamara que está situada a 18 m de distancia. El ángulo de salida del balón es
Brilliant_brown [7]

Answer:

y = 0.99 m

Explanation:

This is a projectile launching exercise, let's start by finding the components of the initial velocity, using trigonometry

         cos θ = v₀ₓ / v₀

         sin θ = v_{oy} / v₀

         v₀ₓ = vo cos θ

         v_{oy} = I go sin θ

         v₀ₓ = 15 cos 30 = 12.99 m / s

         v_{oy} = 15 sin 30 = 7.5 m / s

Let's find the time it takes to travel x = 18 m

         x = v₀ₓ t

         t = x / v₀ₓ

         t = 18 / 12.99

         t = 1,385 s

at this point it is at a height of

         y = v_{oy} - ½ g t²

         y = 7.5 1.385 - ½ 9.8 1.385²

         y = 0.99 m

therefore the camera must place the foot 99 cm from the ground

7 0
3 years ago
What are the different intensity of an earthquake
Masja [62]

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

hope it helps

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5 0
3 years ago
Two linear polarizing filters are placed one behind the other, so that their transmission directions are parallel to one another
ale4655 [162]

Answer:

0.5I0

Explanation:

Because once ligh passes though any polarizer 50% of it is gone.  The second polarizer is also oriented in the same direction so it passes through with no effect.

7 0
4 years ago
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