Answer:
42.96 km/s
Explanation:
From the conservation of Energy
Mass gets cancelled
= Escape velocity of Earth = 11.2 km/s
= Velocity of projectile = 44.4 km/s
The velocity of the spacecraft when it is more than halfway to the star is 42.96 km/s
Answer:
0.28802
2.57162 W
14.28 W
53.55 W
6.07142 W
Explanation:
R = 280Ω
L = 100 mH
C = 0.800 μF
V = 50 V
ω = 10500rad/s
For RLC circuit impedance is given by
Power factor is given by
The power factor is 0.28802
The average power to the circuit is given by
The average power to the circuit is 2.57162 W
Power to resistor
Power to resistor is 14.28 W
Power to inductor
Power to the inductor is 53.55 W
Power to the capacitor
The power to the capacitor is 6.07142 W
Answer:
the vertical position is 1.1971m
Explanation:
Recall that
recall that
this implies that distance = 12 * 5.0
= 60
therefore;
y = 1.1971m
the
Answer:
Approximately .
Explanation:
Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.
Look up the Rydberg constant for hydrogen: .
Look up the speed of light in vacuum: .
Look up Planck's constant: .
Apply the Rydberg formula to find the wavelength (in vacuum) of the photon in question:
.
The frequency of that photon would be:
.
Combine this expression with the Rydberg formula to find the frequency of this photon:
.
Apply the Einstein-Planck equation to find the energy of this photon:
.
(Rounded to three significant figures.)
Answer: Second choice (straight down arrow)
Explanation:
I just did it.