Question

slader A baseball player slides to a stop on level ground. Using energy consideration, calculate the distance the 65 kg baseball player slides, given his initial speed is 6 m/s and the force of friction against him is a constant 450N.

Answer 1

Answer:

2.6 m

Explanation:

From work energy theorem we deduce that

$0.5mv^{2}=fd$

The kinetic energy equals to the work dine against friction energy.

Where m represent mass, v is the velocity, f is the frictional force and d is unknown distance that the player slides.

Making d the subject of the formula then $d=\frac {mv^{2}}{2f}$

Then by substituting 450N for f, 65 kg for m and 6 m/s for v we obtain

$d=\frac {65*6^{2}}{2*450}=2.6m$