Answer:
The Electric flux will be
Explanation:
Given
Strength of the Electric Field at a distance of 0.158 m from the point charge is
We know that the flux of the Electric Field can be calculated by using Gauss Law which is given by
Let consider a sphere of radius 0.158 m as Gaussian Surface at a distance of 0.158 m from the point charge and Let be the flux of the Electric Field coming out\passing through it which is given by
It can be observed that same amount of flux which is passing through the Gaussian sphere of radius 0.158 is also passing through the Gaussian sphere of radius 0.142 m at a distance of 0.142 m from its centre.
Also it can be observed that the charge inside the two Gaussian Sphere mentioned have same value so the Flux of electric field through them will also be same.
So the electric flux through the surface of sphere that has given charge at its centre and that has radius 0.142 m is
Answer:
1500kg
Explanation:
Assuming that the women push the car in the same direction, then the total force is:
Fnet = 425 N ⋅ 3
= 1275 N
To find the mass, we use Newton's second law of motion, which states that,
F = ma
where:
·F is the force applied in newtons
·m is the mass of the object in kilograms
·a is the acceleration of the object in meters per second squared.
So we get:
F
m= ⁻⁻⁻⁻⁻
a
1275N
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
0.85 m/s²
= 1500 kg
Answer:
W = 8.92 10² kJ
Explanation:
For this exercise they give us the strength, we must calculate the distance traveled, for this we need the rocket acceleration let's use Newton's second law
F = m a
a = F / m
a = 20 103/1400
a = 14.29 m/s²
With kinematics we can find the distance traveled
² = v₀² + 2 a x
x = ( ²-v₀²) / 2 a
x = (50² -35²) / 2 14.29
x = 1275 / 28.58
x = 44.61 m
Let's calculate the work
W = F.d
The bold is vector; as indicated by the force is in the direction of movement the scalar product is reduced to the ordinary product
W = F d
W = 20 10³ 44.61
W = 8.92 10⁵ J
W = 8.92 10² kJ
Answer:
Ω
Explanation:
Given that
d(min,0)= 4 cm
d(min,1)= 14 cm
Voltage standingwave ratio = 1.5
Zo = 50 Ω
We know that
d(min,1) - d(min,0) = λ/2
Now by putting the values
14 - 4 = λ/2
λ = 20 cm
We also know that
β=2π/λ
β=2π/0.2 = 10π rad/m
So we can say that
θr= 2β d(min,n) - (2 n + 1)π rad
θr=2×10π ×0.04 −π = -0.2 π rad
We know that
π rad = 180 °
θr= = -0.2 π rad= -36 °
We know that
Here S= 1.5
by putting the values
Ω
Answer:
d license with maintenance .
Explanation:
just took this test. :)