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Anit [1.1K]
3 years ago
14

which narrative point of view uses outside of the story who know. the thoug,feelings,futures and of every character?​

Physics
1 answer:
notka56 [123]3 years ago
5 0
Omniscient - third person who knows how the characters feel and can give the reader unlimited information about them.
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The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = 4.18J/g.K

T_1 = initial temperature of water = 293.0 K

T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0
3 years ago
Write the function of gonads​
navik [9.2K]

Answer:

The gonads, the primary reproductive organs, are the testes in the male and the ovaries in the female. These organs are responsible for producing the sperm and ova, but they also secrete hormones and are considered to be endocrine glands.

7 0
3 years ago
An object is initially moving at an unknown velocity. It accelerates at a rate of 1.5m/s2 to a new velocity of 60 m/s in 25 s. W
Alexandra [31]
<h3>Answer:  22.5 m/s</h3>

=====================================================

Work Shown:

acceleration = ( finalVelocity - initialVelocity )/(change in time)

1.5 = (60 - x)/(25)

1.5*25 = 60-x

37.5 = 60-x

x = 60-37.5

x = 22.5

The initial velocity is 22.5 m/s

6 0
3 years ago
A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then
Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

V=25\ ml = 25\times10^{-6}\ m^3

We need to calculate the buoyancy force

Using formula of buoyancy force

F'= V\rho g

Put the value into the formula

F'=25\times10^{-6}\times1000\times9.8

F'=0.245\ N

We need to calculate the apparent weight of the object

Using formula of apparent weight

W=F-F'

Put the value into the formula

W=0.71-0.245

W=0.465\ N

Hence, The apparent weight of the object is 0.465 N.

5 0
3 years ago
A cube of side 5.0m is in a region where the electric field is directed outward from both of two opposite cube faces, with unifo
guajiro [1.7K]

Answer:

The charge inside the cube is null.

Explanation:

If we apply the gauss theorem with a cubical gaussian surface of the size of the cube:

\displaystyle\oint_{S} \vec{E}\,\vec{ds}=\frac{q_{in}}{\varepsilon_{0}}

If we consider than the direction of the electric field is \vec{E}=E_0\hat{x}, we can solve the problem differentiating  the integral for each face of the cube:

\displaystyle\oint_{S} \vec{E}\,\vec{ds}=\displaystyle\int_{S_1} \vec{E}\,\vec{ds_1}+\displaystyle\int_{S_2} \vec{E}\,\vec{ds_2}+\displaystyle\int_{S_3} \vec{E}\,\vec{ds_3}+\displaystyle\int_{S_4} \vec{E}\,\vec{ds_4}+\displaystyle\int_{S_5} \vec{E}\,\vec{ds_5}+\displaystyle\int_{S_6} \vec{E}\,\vec{ds_6}

\displaystyle\oint_{S} \vec{E}\,\vec{ds}=\displaystyle\int_{S_1} E_0\hat{x}\,\hat{x}ds_1+\displaystyle\int_{S_2} E_0\hat{x}\,\hat{-x}ds_2+\displaystyle\int_{S_3} E_0\hat{x}\,\hat{y}ds_3+\displaystyle\int_{S_4} E_0\hat{x}\,\hat{-y}ds_4+\displaystyle\int_{S_5} E_0\hat{x}\,\hat{z}ds_5+\displaystyle\int_{S_6} E_0\hat{x}\,\hat{-z}ds_6

E₀ is a constant and each surface is equal to each other, so: S_1=S_2=S_i=S

Therefore:

\displaystyle\oint_{S} \vec{E}\,\vec{ds}=E_0\displaystyle\int_{S_1} \,ds_1+E_0\displaystyle\int_{S_2} -1\,ds_2+0+0+0+0=E_0S-E_0S=0

\displaystyle\oint_{S} \vec{E}\,\vec{ds}=0=\frac{q_0}{\varepsilon_0} \longleftrightarrow q_0=0c

3 0
3 years ago
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