Answer:
<em>The power generated is = 5.33×10⁸ Watt. </em>
Explanation:
Power: Power can be defined as the time rate of doing work. The S.I unit of power is <em>Watt(W).</em>
<em>Mathematically,</em>
<em>Power (P) = Work done/time or Energy/time</em>
P = mgh/t............................... Equation 1
P = δgh............................. Equation 2
Where δ = fall rate, g = acceleration due to gravity, h = height.
<em>Given: </em>δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²
Substituting these values into equation 2
P = 1.1×10⁶×49.4×9.81
P = 533.08×10⁶
<em>P = 5.33×10⁸ Watt.</em>
<em>Thus the power generated is = 5.33×10⁸ Watt. </em>
Yes,suns original energy are still stored at the bonds of fossils in which they taken long,long time ago and these fossils powered now industries,fuel for vehicles.In those chemical bonds holds much energy packed together for centuries.
Answer:
Explanation:
energy emitted by source per second = .5 J
Eg = 1.43 eV .
Energy converted into radiation = .5 x .12 = .06 J
energy of one photon = 1.43 eV
= 1.43 x 1.6 x 10⁻¹⁹ J
= 2.288 x 10⁻¹⁹ J .
no of photons generated = .06 / 2.288 x 10⁻¹⁹
= 2.6223 x 10¹⁷
wavelength of photon λ = 1275 / 1.43 nm
= 891.6 nm .
momentum of photon = h / λ ; h is plank's constant
= 6.6 x 10⁻³⁴ / 891.6 x 10⁻⁹
= .0074 x 10⁻²⁵ J.s
Total momentum of all the photons generated
= .0074 x 10⁻²⁵ x 2.6223 x 10¹⁷
= .0194 x 10⁻⁸ Js
b ) spectral width in terms of wavelength = 30 nm
frequency width = ?
n = c / λ , n is frequency , c is velocity of light and λ is wavelength
differentiating both sides
dn = c x dλ / λ²
given dλ = 30 nm
λ = 891.6 nm
dn = 3 x 10⁸ x 30 x 10⁻⁹ / ( 891.6 x 10⁻⁹ )²
= 11.3 x 10¹² Hz .
c )
10 nW = 10 x 10⁻⁹ W
= 10⁻⁸ W .
energy of 50 dB
50 dB = 5 B
I / I₀ = 10⁵ ; decibel scale is logarithmic , I is energy of sound having dB = 50 and I₀ = 10⁻¹² W /s
I = I₀ x 10⁵
= 10⁻¹² x 10⁵
= 10⁻⁷ W
= 10 x 10⁻⁸ W
power required
= 10⁻⁸ + 10 x 10⁻⁸ W
= 11 x 10⁻⁸ W.
Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed = 
= 
= 12m/s
Velocity = 
= = 12m/s due east
Answer:
15.19°, 31.61°, 51.84°
Explanation:
We need to fin the angle for m=1,2,3
We know that the expression for wavelenght is,
Substituting,
Once we have the wavelenght we can find the angle by the equation of the single slit difraction,
Where,
W is the width
m is the integer
the wavelenght
Re-arrange the expression,
For m=1,
For m=2,
For m=3,
<em>The angle of diffraction is directly proportional to the size of the wavelength.</em>
