Answer:
The work required to pump the liquid out of the spout is 2.6 × 10⁶ J
Explanation:
<u>Step 1:</u> consider a spherical tank, sliced into two equal part, since it is half filled.
The new circular surface has a radius, if we construct a right angled-triangle on the surface. The initial radius of the spherical tank becomes the hypotenuse of the triangle and the radius is calculated as follows;
volume (v)
<u>Step 2:</u> Total height, d, in which the liquid is pumped out;
d = b + 3 + 1
= b + 4
<u>Step 3:</u> Force required to pump the liquid out:
F = mg
But, m = density (ρ) x volume (v)
F = ρvg
Given;
ρ = 900 kg/m³ and g = 9.8 m/s²
<u>Step 4:</u> The work done in pumping the liquid out of the spout
W = F x d
Therefore, the work required to pump the liquid out of the spout is 2.6 × 10⁶ J
To solve this problem we will apply the concepts related to wavelength, as well as Rayleigh's Criterion or Optical resolution, the optical limit due to diffraction can be calculated empirically from the following relationship,
Here,
= Wavelength
d= Diameter of aperture
= Angular resolution or diffraction angle
Our values are given as,
The frequency of the sound is
The speed of the sound is
The wavelength of the sound is
Here,
v = Velocity of the wave
f = Frequency
Replacing,
The diffraction condition is then,
Replacing,
d = 0.24 m
Therefore the diameter should be 0.24m
Answer:
The velocity is
Explanation:
From the question we are told that
The initial speed is
The cross -sectional area of the first pipe is
The cross -sectional area of the second pipe is
Generally from continuity equation we have that
So
=>
=>
Answer:
<h3>a) </h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- Rubber is a good conductor of electricity.
<h3>
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h3>
- <em>I</em><em>t</em><em>'</em><em>s</em><em> </em><em>i</em><em>n</em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>s</em><em>e</em><em>n</em><em>t</em><em>e</em><em>n</em><em>c</em><em>e</em><em>.</em>
- As we know that, rubber are an insulators of electricity, and they do not not have free ions which can help in conducting electricity.
<u>S</u><u>o</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>s</u><u>e</u><u>n</u><u>t</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>i</u><u>s</u><u>:</u>
- <em>R</em><em>u</em><em>b</em><em>b</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em> </em><em>b</em><em>a</em><em>d</em><em> </em><em>c</em><em>o</em><em>n</em><em>d</em><em>u</em><em>c</em><em>t</em><em>o</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>r</em><em>i</em><em>c</em><em>i</em><em>t</em><em>y</em><em>.</em>
<h3>b)</h3><h3>
<u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h3>
- Electroplating wastes are useful to human health and environment.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em>.</em><em> </em>
- As we know that, electroplating of substances releases harmful and toxic substances into the environment causing serious health issues in human, so it's waste substances released into environment can have very harmful effects.
<u>So correct sentence is:</u>
- <em>Electroplating wastes are </em><em>harmful</em><em> </em><em>to human health and </em><em>environment</em><em>.</em>
<h3>
c)</h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- In an LED bulb, the shorter lead is connected to the positive terminal of the battery.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's incorrect sentence. </em>
- As we know that, in an LED bulb their are two terminals that is the positive and the negative. So here the lead connected to the positive terminal is always slightly longer than the lead connected to negative terminal of the bulb.
<u>So correct sentence is:</u>
- <em>In an LED bulb, the </em><em>longer</em><em> lead </em><em>i</em><em>s</em><em> </em><em>connected to the positive terminal of the battery.</em>
<h3>
d)</h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- Pure water conducts electricity.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's incorrect sentence. </em>
- As we know that, pure water is a form of H2O where Hydrogen (H) is positive ion and Oxygen (O) is a negative ion which can conduct electricity when they are in individuals but as in pure water they are in combined form of compound H2O in which they become neutral and can't conduct any electricity.
<u>So correct sentence is:</u>
- <em>P</em><em>ure water </em><em>c</em><em>a</em><em>n</em><em>'</em><em>t</em><em> </em><em>conduct</em><em> </em><em>electricity.</em>
Ek (Kinetic Energy) = 1/2m*v^2
0.5x1x30^2
0.5x30^2
= 450J (joules)