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____ [38]
3 years ago
10

What is the number of elements for 2C3H5O2

Chemistry
1 answer:
ch4aika [34]3 years ago
7 0

Answer: Total Number of Atoms is Nine.

We have 3 atoms of (C)carbon, 5 atoms of (H)hydrogen and 2 atoms of (O)oxygen. So total is 3+5+2=10

It means there are 10 atoms in the compound and from the formula we come to know that there are 2 molecules . Therefore 2×10=20 atoms.

C3 means there are 3 atoms of carbon in one molecule

3C means just 3 atoms of carbon

3C3 means there are 3 molecules of carbon with 3 carbon atoms in each molecule. So total atoms is 9.

Hope I helped!

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Which of the following is a homogeneous mixture? a. Na(s) b. H2O(l) c. Cl2(g) d. NaCl(aq)
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An unknown compound, X is thought to have a carboxyl group with a pKa of 2.0 and another ionizable group with a pKa between 5 an
Westkost [7]

Answer:

7.3

Explanation:

By Henderson Hasselbalch equation we can calculate the pH or the pOH of a solution by its pKa. Remember that pH = -log[H^{+}], and pKa = -logKa. Ka is the equilibrium constant of the acid.

Henderson Hasselbalch equation :

pH = pKa - log \frac{[HA]}{[A^{-}]}

Where [HA] is the concentration of the acid, and [A^{-}] is the concentration of the anion which forms the acid.

So, acid X, has two ionic forms, the carboxyl group and the other one. First, we have 0.1 mol/L of the acid, in 100 mL, so the number of moles of X

n1 = (0.1 mol/L)x(0.1 L) = 0.01 mol

When it dissociates, it forms 0.005 mol of the carboxyl group and 0.005 mol of the other group. Assuming same  stoichiometry.

Adding NaOH, with 0.1 mol/L and 75 mL, the number of moles of OH^- will be

n2 = (0.1 mol/L)x(0.075 L) = 0.0075 mol

So, the 0.0075 mol of OH^- reacts with 0.005 mol of carboxyl, remaining 0.0025 mol of OH^-, which will react with the 0.005 mol of the other group. So, it will remain 0.0025 mol of the other group.

The final volume of the solution will be 175 mL, but both concentrations (the acid form and ionic form) have the same volume, so we can use the number of mol in the equation.

Note that, the number of moles of the acid form is still 0.01 mol because it doesn't react!

So,

6.72 = pKa - log \frac{0.01}{0.0025}

6.72 = pKa - log 4

pKa - log4 = 6.72

pKa = 6.72 + log4

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