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liberstina [14]
3 years ago
5

Rabbits are best described as _______.

Chemistry
1 answer:
Otrada [13]3 years ago
7 0

Answer:  its actually primary consumers

Explanation:

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assume that a water balloon has the same number of water molecules as a helium balloon has helium atoms. If the mass of the wate
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Answer : The mass of the water molecule is 4.5 times greater than the mass of the helium atom.

Explanation :

Assumption : The number of water molecules is equal to the number of helium atoms

Given : The mass of water = 4.5 × The mass of helium     ........(1)

The mass of Water = Mass of 1 water molecule × Number of water molecule

The mass of Helium = Mass of 1 helium atom × Number of helium atom

Now these two masses expression put in the equation (1), we get

Mass of 1 water molecule × Number of water molecule = 4.5 × Mass of 1 helium atom × Number of helium atom

As per assumption, the number of water molecules is equal to the number of helium atoms. The relation between the mass of water molecule and the mass of helium atom is,

Mass of water molecule = 4.5 × Mass of helium atom

Therefore, the mass of the water molecule is 4.5 times greater than the mass of the helium atom.

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Water is a pure substance. Which of the following is true about water? (4 points) Its compounds can only be physically separated
jonny [76]

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Water/H20 is a compound made of hydrogen and oxygen. Although water is the most abundant substance on earth, it is rarely found naturally in its pure form. Most of the time, pure water has to be created. Pure water is called distilled water or deionized water.

Explanation:

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8 0
3 years ago
Read 2 more answers
What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances
belka [17]

The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.

Isotope                    mass amu        Relative abundance

1                                77.9                     14.4

2                               81.9                     14.3

3                               85.9                      71.3

Express your answer to three significant figures and include the appropriate units.

Answer: 84.2 amu

Explanation:

Mass of isotope 1 = 77.9  

% abundance of isotope 1 = 14.4% = \frac{14.4}{100}=0.144

Mass of isotope 2 = 81.9

% abundance of isotope 2 = 14.3% = \frac{14.3}{100}=0.143

Mass of isotope 3 = 85.9

% abundance of isotope 2 = 71.3% = \frac{71.3}{100}=0.713

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(77.9\times 0.144)+(81.9\times 0.143)+(85.9\times 0.713)]

A=84.2amu

Therefore, the average atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances is 84.2 amu

4 0
3 years ago
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