Answer : The concentration of the 
is, 0.115 M
Explanation :
Using dilution law,
where,
= basicity of an acid = 1
= acidity of a base = 1
= concentration of 
= 0.125 M
= concentration of KOH = ?
= volume of = 25 ml
= volume of NaOH = 27.07 ml
Now put all the given values in the above law, we get the concentration of the .
Therefore, the concentration of the is, 0.115 M
Chemical formulas are used to describe the types of atoms and their numbers in an element or compound. The atoms of each element are represented by one or two different letters. When more than one atom of a specific element is found in a molecule, a subscript is used to indicate this in the chemical formula.
So if it is 2.35L at the temperature 20.0^C and you want the volume at -5.00^C this is hw you would solve it for example 20.0^C to 2.00L it would be 10 degrees per Liter so it would be here 10 degrees every liter so you would do 20.0 % 2.35 = / then find the answer and then find out how many degrees that answer is off of -5.00 then once you get that divide -5.00 with that answer.<span>
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The given question is incomplete. The complete question is:
How much heat is produced when 24.8 g of 
is burned in excess oxygen gas
Given: 
ΔH= −802 kJ.
Answer: 1243.1 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 
of particles.
1 mole of weighs = 16 g
Thus we can say:
16 g of on combustion releases heat = 802 kJ
Thus 24.8 g of on combustion releases =
Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ
The answer to this question would be true.
