Question

At the bottom of a hill, a car has an initial velocity of +16.0 meters per second. The car is uniformly accelerated at -2.20 meters per second squared for 5.00 seconds as it moves up the hill. How far does the car travel during this 5.00-second interval?
1.) 107m
2.) 74.5m
3.) 52.5m
4.)25.0m

Answer 1

Answer:

3) 52.5 m

Explanation:

d = v₁t + 1/2at²

d = 16 m/s (5s) + 1/2(-2.2m/s²) (5s)²  = 52.5 m