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Nastasia [14]
3 years ago
9

Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9

2×1016Cl− ions arrive at the positive electrode.
Part A.) What is the current passing between the electrodes? (answer in mA)
Part B.) What is the direction of the current in the ionic solution? (answer is either away from the negative electrode or towards the negative electrode)

Physics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

a) 10.56mA the current passing between the electrodes

b) away from the negative charge

Explanation:

The detailed step by step calculation is as shown in the atached file.

By Application of faradays first law of electrolysis. i.e Q = it

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C.........................
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Fehling's solution is added to the counters of test tube b after about 3 minutes and it turns brick red.what food substance was
hjlf

The food substance being used which turned Fehling's solution to brick red is a reducing sugar.

<h3>What is Fehling's solution?</h3>

This is an indicator which is used to test for the presence of reducing sugar or aldehydes in a solution.

Brick red precipitate of copper(I) oxide is formed when it tests positive to compounds such as glucose etc.

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2 years ago
A cyclist turns a corner with a radius of 50m at a speed of 10m/s. What is the cyclist's acceleration?
miv72 [106K]

2m/s²

Explanation:

Given parameters:

Radius = 50m

Speed = 10m/s

Unknown:

Acceleration of the cyclist

Solution:

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     a = \frac{v^{2} }{r}

v is the velocity

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3 0
3 years ago
A space vehicle is traveling at 5425 km/h relative to the Earth when the exhausted rocket motor (mass 4m) is disengaged and sent
lana66690 [7]

Answer:

V_{cE}=1489m/s

Explanation:

Given data

Space vehicle speed=5425 km/h relative to earth

The rocket motor speed=81 km/h  and mass 4m

The command has mass m

From the conservation of momentum as the system isolated

p_{i}=p_{f}\\

Since the motion in on direction we can drop the unit vector direction

MV_{i}=4mV_{mE}+mV_{CE}

Where M is the mass of space vehicle which equals to sum of the motors mass and command mass.

The velocity of the motor relative to the earth equals the velocity of the motor relative to command plus the velocity of the command relative to earth

V_{mE}=V_{mc}+V_{cE}

Where Vmc is the velocity of motor relative to command

This yields

5mV_{i}=4m(V_{mc}+V_{cE})+mV_{cE}\\5V_{i}=4V_{mc}+5V_{cE}

Substitute the given values

V_{cE}=\frac{5V_{i}-4V_{mc}}{5}\\ V_{cE}=5425*\frac{1000}{60*60}(m/s)-\frac{4}{5}*81\frac{1000}{60*60}(m/s)\\  V_{cE}=1489m/s

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3 years ago
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mixer [17]
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