Answer:
W = 76 N
Explanation:
In this exercise you are asked to find the weight of the body.
Mass is a quantity that is invariant, it measures the same everywhere, the weight depends on where it is measured, a simple way to find the weight of a body is
W = g m
where g is the constant of the place, in this case we have the weight of the body on Mars and its mass which is constant on Earth and on Mars
W = 3.8 20
W = 76 N
Answer:
It comes out the positive side of the battery and goes in to the negative side of the battery
Explanation:
There are already electrons in wires in a circuit before you add the battery. By adding the battery, you're giving the electrons the energy it needs to move along the circuit.
In a series circuit, the circuit is one continuous loop so there is only one path for the electrons to go - out of the positive side of the battery and around the circuit then goes back into the negative side of the battery.
However, with a parallel circuit, there are two or more ways the electrons can go so they take the path of least resistance. The electrons still go out the positive side of a battery but along the circuit, the electrons will go through the path of least resistance ( I tend to think of it like a net with holes in it - the lower the resistance the bigger the holes for the electrons to go through so more can fit in a set amount of time ) but the electrons still go out of the positive side and in through the negative
Answer:
1.65 kg.m/s
Explanation:
mass of ball (m) = 0.13 kg
initial speed (u) = 18 m/s
acceleration due to gravity (g) = 9.81 m/s^{2}
angle of projection (p) = 90°
to find the momentum half way to its maximum height we first have to know the maximum height, and the velocity at the maximum height.
maximum height (h) =
maximum height (h) = = 16.53 m
velocity at half the maximum height (v) can be gotten from the equation of motion
( the negative sign is because the ball is moving upwards)
v =
v= 12.72 m/s
momentum of the ball half way to its maximum height = mass x velocity = 0.13 x 12.72 = 1.65 kg.m/s
Answer: option D. the ratio of the population of male deer is not constant.
Explanation:
The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.
These features are remarkable:
- The polulation of male deer (blue bars) decrease from 1961 to 1971, then increase in the next 10 year, decrease in the next decade, and increase for the next two decades. So, its trend is erratic, with ups and downs.
This discards the option A, which states that the population of male deer increases each decade from 1961 to 2011.
- The population of female deer (purple or brown bars) decreases every decade.
This discards the option B. which states that when the polulation of male deer increases, the poluplation of female deer also increases.
- The populations never are equal, hence this discards the option C.
- Since, one popultion increases and decreases, while the other population only decreases, you conclude that the ratio of the population of male deer to female deer is not constant, which is the option D.