All categories

2 years ago

What is the speed of a wave that has a frequency of 2,400 Hz and a wavelength of 0.75

Physics

1 answer:

likoan [24]2 years ago

6 0

Answer:

1800 m/s

Explanation:

The equation is v = fλ

λ= 0.75

f = 2400 Hz

V = 2400 × 0.75

V = 1800 m/s

[ you did not give units for wavelength, I assumed it would be m/s]

You might be interested in

A car travels 300km in six hour. What is the average speed

KiRa [710]

Answer:

Explanation:

The average speed of the car can be found by using the formula

$s = \frac{d}{t} \\$

d is the distance

t is the time taken

From the question we have

$s = \frac{300}{6} = 50 \\$

We have the final answer as

Hope this helps you

5 0

2 years ago

Which group of stars is represented by the line image

Lerok [7]

Answer:

ursa Major

Explanation:

8 0

3 years ago

Read 2 more answers

A Micro –Hydro turbine generator is accelerating uniformly from an angular velocity of 610 rpm to its operating angular velocity

Salsk061 [2.6K]

Answer:

Angular displacement of the turbine is 234.62 radian

Explanation:

initial angular speed of the turbine is

$\omega_i = 2\pi f_1$

$\omega_1 = 2\pi(\frac{610}{60})$

$\omega_1 = 63.88 rad/s$

similarly final angular speed is given as

$\omega_f = 2\pi f_2$

$\omega_2 = 2\pi(\frac{837}{60})$

$\omega_2 = 87.65 rad/s$

angular acceleration of the turbine is given as

$\alpha = 5.9 rad/s^2$

now we have to find the angular displacement is given as

$\theta = \omega t + \frac{1}{2}\alpha t^2$

$\theta = (63.88)(3.2) + (\frac{1}{2})(5.9)(3.2^2)$

$\theta = 234.62 radian$

3 0

2 years ago

Total internal reflection will occur when:

ollegr [7]

Answer:

Try B or C if I'm wrong sorry

Explanation:

3 0

1 year ago

Two parallel plates that are initially uncharged are separated by 1.2 mm. What charge must be transferred from one plate to the

Gnoma [55]

Answer: 55.52 *10^-6 C= 55.52 μC

Explanation: In order to solve this question we have to take into account the following expressions:

potential energy stired in a capacitor is given by:

U=Q^2/(2*C) where Q and C are the charge and capacitance of the capacitor.

then we have:

Q^2= 2*C*U=

C=εo*A/d where A and d are the area and separation of the parallel plates capacitor

Q^2=2*εo*A*U/d=2*8.85*10^-12*1.9*10^-5*11*10^3/(1.2*10^-3)=

=55.52 *10^-6C

4 0

2 years ago