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WITCHER [35]
3 years ago
9

Please help me with physics homework! Provide explanation.

Physics
1 answer:
zaharov [31]3 years ago
3 0
The direction of friction force is always the opposite of the direction of the movement.

In this problem, we have an applied force of 20N and this creates a movement. Then, the friction comes in and applies a force of 2.4N.

Because they are in different directions, we need to subtract them:
20 - 2.4 = x \\  \\ x = 17.6
We don't know the direction because there is no picture (at least I can't see ☺️). But the movement will be to the direction of the 20N.
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B. a generator

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When work is done on an object, where does the energy used to do the work go?
borishaifa [10]
-- If the work is done to make the object move faster, then
the work done becomes kinetic energy of the object.

-- If work is done on the object but it doesn't move any faster,
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PLEASE HELP SOON
Kitty [74]

Answer:you in connections too?

Explanation:

7 0
3 years ago
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At what position or positions on the x-axis is the electric field zero?
ElenaW [278]

Answer:

The electric field will be zero at x = ± ∞.

Explanation:

Suppose, A -2.0 nC charge and a +2.0 nC charge are located on the x-axis at x = -1.0 cm and x = +1.0 cm respectively.

We know that,

The electric field is

E=\dfrac{kq}{r^2}

The electric field vector due to charge one

\vec{E_{1}}=\dfrac{kq_{1}}{r_{1}^2}(\hat{x})

The electric field vector due to charge second

\vec{E_{2}}=\dfrac{kq_{2}}{r_{2}^2}(-\hat{x})

We need to calculate the electric field

Using formula of net electric field

\vec{E}=\vec{E_{1}}+\vec{E_{2}}

\vec{E_{1}}+\vec{E_{2}}=0

Put the value into the formula

\dfrac{kq_{1}}{r_{1}^2}(\hat{x})+\dfrac{kq_{2}}{r_{2}^2}(-\hat{x})=0

\dfrac{kq_{1}}{r_{1}^2}(\hat{x})=\dfrac{kq_{2}}{r_{2}^2}(\hat{x})

(\dfrac{r_{2}}{r_{1}})^2=\dfrac{q_{2}}{q_{1}}

\dfrac{r_{2}}{r_{1}}=\sqrt{\dfrac{q_{2}}{q_{1}}}

Put the value into the formula

\dfrac{2.0+x}{x}=\pm\sqrt{\dfrac{2.0}{2.0}}

2.0+x=x

If x = ∞, then the equation is be satisfied.

Hence, The electric field will be zero at x = ± ∞.

4 0
3 years ago
Tony has a mass of 50 kg, and his friend Sam has a mass of 45 kg. Assume that both friends push off on their rollerblades with t
Citrus2011 [14]

Answer:

Sam

Explanation:

Hes lighter

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3 years ago
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