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WITCHER [35]
3 years ago
9

Please help me with physics homework! Provide explanation.

Physics
1 answer:
zaharov [31]3 years ago
3 0
The direction of friction force is always the opposite of the direction of the movement.

In this problem, we have an applied force of 20N and this creates a movement. Then, the friction comes in and applies a force of 2.4N.

Because they are in different directions, we need to subtract them:
20 - 2.4 = x \\  \\ x = 17.6
We don't know the direction because there is no picture (at least I can't see ☺️). But the movement will be to the direction of the 20N.
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Answer:

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A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is
ivanzaharov [21]
<span>anwser will be 

F = ma

where 

F = force exerted on the bullet 
m = mass of the bullet = 5 gm (given) = 0.005 kg. 
a = acceleration of the bullet 

Substituting appropriately, 

F = 0.005a --- call this Equation 1 

Next working equation is 

Vf^2 - Vo^2 = 2as 

where 

Vf = velocity of the bullet as it leaves the muzzle = 326 m/sec (given) 
Vo = initial velocity of bullet = 0 
a = acceleration of bullet 
s = length of the rifle's barrel 

Substituting appropriately, 

326^2 - 0 = 2(a)(0.83) 

a = 64,022 m/sec^2 

the anwser will be
Substituting this into Equation 1, 

F = 0.005(64,022) 

F =320.11 Newtons 

Hope this helps. </span><span>
</span>
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3 years ago
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This seems like a calculus problem. I'm assuming you would use cos and sin. so here's the vertical component +10.0m/s multiplied by sin60 = 8.66 rounded to the hundreths place. Now for horizontal, that would be +10.0m/s multiplied by cos60 = 5. hope this helped.
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3 years ago
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