Answer:
ωB = 300 rad/s
ωC = 600 rad/s
Explanation:
The linear velocity of the belt is the same at pulley A as it is at pulley D.
vA = vD
ωA rA = ωD rD
ωD = (rA / rD) ωA
Pulley B has the same angular velocity as pulley D.
ωB = ωD
The linear velocity of the belt is the same at pulley B as it is at pulley C.
vB = vC
ωB rB = ωC rC
ωC = (rB / rC) ωB
Given:
ω₀A = 40 rad/s
αA = 20 rad/s²
t = 3 s
Find: ωA
ω = αt + ω₀
ωA = (20 rad/s²) (3 s) + 40 rad/s
ωA = 100 rad/s
ωD = (rA / rD) ωA = (75 mm / 25 mm) (100 rad/s) = 300 rad/s
ωB = ωD = 300 rad/s
ωC = (rB / rC) ωB = (100 mm / 50 mm) (300 rad/s) = 600 rad/s
(1,500 meters) x (1 sec/330 meters) =
(1,500 / 330) (meters-sec/meters) =
4.55 seconds
The elements found in the Group 1, or the Alkali Metal Group, have electronic configurations that end in

.This means that they have 1 electron readily available to release in order to achieve a stable state.
When these atoms release the valence electron, they will achieve a stable state. For example, Lithium's stable state will be

and Sodium will be

.
The oxidation state will then be +1.
The answer is C.
The force and amount of attracton is great for larger masses
Answer:
D) examine a person for diseases
Explanation:
Only an X-ray can examine a person for diseases and broken bones because it is used to see what is happening on the inside of our bodies.