All categories

3 years ago

A body builder exerts 15 N of force over 3 m. How much work did she do?

Physics

2 answers:

tangare [24]3 years ago

4 0

Work done = force x distance

work done = 15 x 3

work done = 45J

eimsori [14]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf 45 \ Joules}}$

Explanation:

Work is the force the causes the movement or displacement of an object. It is the product of force and displacement.

$W=Fd$

The force is 15 Newtons and the displacement is 3 meters.

F= 15 N
d= 3 m

Substitute the values into the formula.

$W= 15 \ N * 3 \ m$

Multiply.

$W= 45 \ N*m$

1 Newton meter is equal to 1 Joule, so our answer of 45 Newton meters is equal to 45 Joules.

You might be interested in

How can I become a good science student ?

iris [78.8K]

Answer:

Study hard , focus on your studies and alyways ask questions .

7 0

2 years ago

Read 2 more answers

Which has more momentum, a heavy truck moving at 30 miles per hour or a light truck moving at 30 miles per hour?

valentina_108 [34]

A heavy truck moving a 30 mph. It has more mass.

7 0

3 years ago

Read 2 more answers

[7 pts] 1. Suppose that a car starts from rest, its engine providing an acceleration of 4 ft/s2 while air resistance provides 0.

kumpel [21]

Answer:

a) Initial Value Problem

dv/dt = 4 - 0.1v

v(0) = 0

b) solution to the IVP

v(t) = 40(1 - e^(-t/10))

c) Limiting velocity

Vo = 40 ft/s

Position of the car after 12 hours

X = 14,390 ft

Explanations:

The complete explanations of each of the sections contained in the question are in the files attached to this solution.

4 0

3 years ago

1. What are electromagnetic waves?

Wewaii [24]

las ondas electromagnéticasSon aquellas ondas que no necesitan un medio material para propagarse. Incluyen, entre otras, la luz visible y las ondas de radio, televisión y telefonía. ... Las ondas electromagnéticas se propagan mediante una oscilación de campos eléctricos y magnéticos.

8 0

3 years ago

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the d

frez [133]

The question is incomplete. Here is the complete question.

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is

$\beta=10log(\frac{I}{I_{0}} )dB$ ,

where $I_{0}$ is a reference intensity. for sound waves, $I_{0}$ is taken to be $10^{-12} W/m^{2}$ . Note that log refers to the logarithm to the base 10.

Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. $I=10I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. $I=100I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part C: Calculate the change in decibels ( $\Delta \beta_{2},\Delta \beta_{4}$ and $\Delta \beta_{8}$ ) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.