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slava [35]
3 years ago
14

One container has 100 mL of water and a second container has 1000 mL of water. If the temperature in both containers is 22 C (71

.6 F). Which container has the greatest amount of thermal energy and why?
Physics
2 answers:
kicyunya [14]3 years ago
5 0
The 100 mL because it has less space to fill up with the tenperature
kow [346]3 years ago
5 0

Answer:

1000 mL of water

Explanation:

The thermal energy of a substance is the total amount of energy- potential and kinetic energy contained in it. It depends on the temperature, mass and phase of the substance.

Since, the both the containers contain liquid water at same temperature, greater mass would have greater thermal energy. Thus, container having 1000 mL of water would have greater thermal energy.

(mass =density x volume

because, density is same, mass ∝ volume

greater volume means more mass)

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vekshin1
Liquids is the answer
5 0
3 years ago
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If an object is accelerating, it is traveling the same distance for each time interval of its motion
Anika [276]

Answer:

false

Explanation:

if an object is accelerating the object will not travel the same distance every time interval

4 0
3 years ago
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What will be the weight of a man of mass 90kg when he is on a planet with acceleration due to gravity of 15ms-2?
Feliz [49]

Answer:

1350N

Explanation:

Weight = Mass x Acceleration Due to Gravity

W=mg

W=90*15=1350N

7 0
4 years ago
Two boats leave the same port at the same time, with boat A traveling north at 15 knots (nautical miles per hour) and boat B tra
Mrrafil [7]

Answer:

The chance in distance is 25 knots

Explanation:

The distance between the two particles is given by:

s^2 = (x_A - x_B)^2+(y_A - y_B)^2  (1)

Since A is traveling north and B is traveling east we can say that their displacement vector are perpendicular and therefore (1) transformed as:

s^2 = x_B^2+y_A^2 (2)

Taking the differential with respect to time:

\displaystyle{2s\frac{ds}{dt}= 2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt}}  (3)

where \displaystyle{\frac{dx_B}{dt}}=v_B and \displaystyle{\frac{dx_A}{dt}}=v_A are the respective given velocities of the boats. To find s and x_B we make use of the given position for A, y_A=30, the Pythagoras theorem and the relation between distance and velocity for a movement with constant velocity.

\displaystyle{y_A = v_A\cdot t\rightarrow t = \frac{y_A}{v_A}=\frac{30}{15}=2 h

with this time, we know can now calculate the distance at which B is:

\displaystyle{x_B = v_B\cdot t= 20 \cdot 2 = 40\ nmi

and applying Pythagoras:

\displaystyle{s = \sqrt{x_B^2+y_A^2}=\sqrt{30^2 + 40^2}=\sqrt{2500}=50}

Now substituting all the values in (3) and solving for  \displaystyle{\frac{ds}{dt} } we get:

\displaystyle{\frac{ds}{dt} = \frac{1}{2s}(2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt})}\\\displaystyle{\frac{ds}{dt} = 25 \ knots}

4 0
3 years ago
What is the magnitude of the change in potential energy of the block-spring system when it travels from its lowest vertical posi
maksim [4K]

Answer:

 ΔU = 2 mg h

Explanation:

In a spring mass system the potential energy is U = m g h

where h is measured from the equilibrium point of the spring

the potential energy at the highest point is

         U₁ = m g h

the potential energy at the lowest point is

         U₂ = m g (-h)

instead in this energy it is

          ΔU = 2 mg h

In this two points the kinetic energy is zero, but there is elastic potential energy that has the same value in the two points, so its change is zero

4 0
3 years ago
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