Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150
1 answer:
Answer:
The temperature of the core raises by every second.
Explanation:
Since the average specific heat of the reactor core is 0.3349 kJ/kgC
It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius
Thus reactor core whose mass is will require
energy to raise it's temperature by 1 degree Celsius in 1 second
Hence by the concept of proportionately we can infer 150 MW of power will increase the temperature by
You might be interested in
Answer:
The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.
Explanation:
Let assume the existence of a line of current between the water tank and the ground and, hence, the absence of heat and work interactions throughout the system. If water is approximately at rest at water tank and at atmospheric pressure (), then speed of efflux of the non-viscous water is modelled after the Bernoulli's Principle:
Where:
,
- Water total pressures inside the tank and at ground level, measured in pascals.
- Water density, measured in kilograms per cubic meter.
- Gravitational acceleration, measured in meters per square second.
,
- Water speeds inside the tank and at the ground level, measured in meters per second.
,
- Heights of the tank and ground level, measured in meters.
Given that ,
,
,
,
and
, the expression is reduced to this:
And final speed is now calculated after clearing it:
The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.
Please find attached photograph for your answer. Answer is c. 16 times. Do comment if you have any query. Don't forget to mark me Brainliest if you like my answer
