Range of a projectile motion is given by
R = v cos θ / g (v sin θ + sqrt(v^2 sin^2 θ + 2gy_0)); where R = 188m, θ = 41°, g = 9.8m/s^2, y_0 = 0.9
188 = v cos 41° / 9.8 (v sin 41° + sqrt(v^2 sin^2 41° + 2 x 9.8 x 0.9)) = 0.07701(0.6561v + sqrt(0.4304 v^2 + 17.64)) = 0.05053v + 0.07701sqrt(0.4304v^2 + 17.64)
0.07701sqrt(0.4304v^2 + 17.64) = 188 - 0.05053v
0.005931(0.4304v^2 + 17.64) = 35344 - 19v + 0.002553v^2
0.002553v^2 + 0.1046 = 35344 - 19v + 0.002553v^2
19v = 35344 - 0.1046 = 35343.8954
v = 35343.8954/19 = 1860 m/s
Answer:
0.43 m
Explanation:
Angle of incident and angle of reflection is same.
tan Θh = L' / x (eye)
L' = Length of the window
x (eye) = Distance of the mirror from the eye
tan Θh = L / (x (eye) + xw)
xw = Distance of the mirror from the window
L'/ x (eye) = L / ( x (eye) + xw)
L' = L*x (eye) / ( x (eye) + xw)
L' = (2*0.5) / (0.5 + 1.8)
L' = 0.43 m
Answer:
(a) the blocks all had different masses.
Explanation:
The surface is smooth, therefore coefficient of friction is tending to zero.
Forces for each blocks varied from 6N to 8N to 7N to 5N
The blocks were made of different materials and different materials are going to have varying weight for the same size of block.
Complete question:
It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?
Answer:
The specific gravity of the oil is 0.8.
Explanation:
Given;
density of the oil, 
= 800 kg/m³
density of water, 
= 1000 kg/m³
The specific gravity of any substance is the ratio of the substance density to the density of water.
Specific gravity of the oil = density of the oil / density of water
Specific gravity of the oil = 800/1000
Specific gravity of the oil = 0.8
Therefore, the specific gravity of the oil is 0.8.
Answer :
New force becomes, F' = 1.83 N
Explanation:
Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :
are charges
r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r
New force is given by :
F' = 1.83 N
So, the new force between charges will be 1.83 N. Therefore, this is the required solution.
