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densk [106]
3 years ago
7

Consider the reversible reaction in aqueous medium shown below. At equilibrium, the concentrations of A, B, C, and D are 0.0053

M, 0.0085 M, 0.0040 M, and 0.0035 M, respectively. What is the equilibrium constant for the reaction? A+3B⇌3C+D
Chemistry
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

The equilibrium constant for the reaction is 0.0689

Explanation:

<u>Step 1:</u> Data given

The concentrations of A = 0.0053 M

The concentration of B = 0.0085 M

The concentration of C = 0.0040 M

The concentration of D = 0.0035 M

<u>Step 2:</u> The balanced equation:

A+3B⇌3C+D

<u>Step 3:</u> Calculate the equilibrium constant

K = [C]³[D] / [A][B]³

K = (0.0040)³(0.0035) / (0.0053)(0.0085)³

K = 0.0689

The equilibrium constant for the reaction is 0.0689

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