How many moles of CaCl2 are contained in 0.448 L of a 0.85 M CaCl2 solution?
1 answer:
You might be interested in
Answer: The correct option is
Explanation:
Atomic mass of calcium ,Ca = 40.07 g/mol
Atomic mass of chlorine ,Cl = 35.5 g/mol
Molar mass of :
= (Atomic mass of Ca+2 × (Atomic mass of Cl))
= (40.07 g/mol + (2 × 35.5))=111.07 g/mol
Hence, the correct option is
<u>Answer:</u> The number of moles of ethanol after equilibrium is reached the second time is 11. moles.
<u>Explanation:</u>
We are given:
Initial moles of ethene = 34 moles
Initial moles of water vapor = 15 moles
The chemical equation for the formation of ethanol follows:
Initial: 34 15
At eqllm: 34-x 15-x x
We are given:
Equilibrium moles of ethene = 24 moles
Equilibrium moles of water vapor = 5 moles
Calculating for 'x'. we get:
Volume of container = 100.0 L
The expression of for above equation follows:
.......(1)
Putting values in expression 1, we get:
Now, 11 moles of ethene gas is again added and equilibrium is re-established, we get:
The chemical equation for the formation of ethanol follows:
Initial: 24+11 5 10
At eqllm: 35-x 5-x 10+x
Putting values of in expression 1, we get:
The value of 'x' cannot exceed '35', so the numerical value of x = 50.9 is neglected.
Moles of ethanol =
Hence, the number of moles of ethanol after equilibrium is reached the second time is 11. moles.