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marissa [1.9K]
3 years ago
10

How many moles of CaCl2 are contained in 0.448 L of a 0.85 M CaCl2 solution?

Chemistry
1 answer:
kati45 [8]3 years ago
3 0

Answer:

0.3808

Explanation:

number of moles,n=Conc.XVol.

hence 0.85X0.448

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The empirical formula is = FeCl_{3}

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