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marissa [1.9K]
3 years ago
10

How many moles of CaCl2 are contained in 0.448 L of a 0.85 M CaCl2 solution?

Chemistry
1 answer:
kati45 [8]3 years ago
3 0

Answer:

0.3808

Explanation:

number of moles,n=Conc.XVol.

hence 0.85X0.448

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Using the following equation: 3H2SO4+ 2Fe -> Fe2(SO4)3+ 3H2
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Answer:

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Explanation:

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Chemical equation:

3H₂SO₄  + 2Fe      →          Fe₂(SO₄)₃  + 3H₂

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               H₂SO₄         :          Fe₂(SO₄)₃  

                  3               :              1

                 15               :              1/3×15 = 5

                H₂SO₄         :            H₂

                  3               :              3

                 15               :              15

                Fe               :          Fe₂(SO₄)₃  

                  2               :              1

                 13               :              1/2×13 = 6.5

                Fe               :                H₂

                  2               :                 3

                 13               :              3/2×13 = 19.5

Number of moles of product formed by  H₂SO₄ are less thus it will act as limiting reactant.

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