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Arlecino [84]
3 years ago
15

Answer and I will give you brainiliest

Physics
2 answers:
Snezhnost [94]3 years ago
6 0
A statement of what someone thinks will happen
svp [43]3 years ago
3 0
The answer to the question is C
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Ocean water conducts electrical current because it contains _____.
icang [17]
<span>Ocean water conducts electrical current because it contains electrolytes. Electrolytes are good conductors of electricity, and are naturally present in appropriate amounts in bodies of water. However, pure water (without electrolytes or metals) is not a conductor of electricity. </span>
3 0
3 years ago
Read 2 more answers
Vector B has x, y, and z components of 2.4,
Fed [463]

The magnitude of the vector B is 10.9

A vector is a quantity which has magnitude as well as direction and it follows vector laws of addition.

To calculate the magnitude of the vector, we have to put the square of the components of the vector along the axes under the root.

Vector B has components,

x = 2.4

y = 9.8

z = 4.1

Applying the formula,

|B| = √x²+y²+z²

|B| = √(2.4)² + (9.8)² + (4.1)²

|B| = √5.76+96.04+16.81

|B| = √118.61

|B| = 10.9

Talking about the direction the the Vector B, it will be the line joining the origin with the points (2.4,9.8,4.1)

To know more about Vectors, visit,

brainly.com/question/25705666

#SPJ9

3 0
1 year ago
How tall would a tower need to be if the period of a pendulum were 30. seconds
Virty [35]
We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
4 0
3 years ago
At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball
dedylja [7]

Answer:

Magnitude of net force will be 432.758 N  

Explanation:

We have given x component of acceleration a_x=760m/sec^2

And vertical component of acceleration  a_y=770m/sec^2

Mass of the ball m = 0.40 kg

So net acceleration a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

3 0
3 years ago
Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of
vredina [299]

Answer:

The angular speed after 6s  is \omega = 1466.67s^{-1}.

Explanation:

The equation

I\alpha  = Fd

relates the moment of inertia I of a rigid body, and its angular acceleration \alpha, with the force applied F at a distance d from the axis of rotation.

In our case, the force applied is F = 22N, at a distance d = 6cm =0.06m, to a ring with the moment of inertia of I =mr^2; therefore, the angular acceleration is

$\alpha =\frac{Fd}{I} $

$\alpha =\frac{22N*0.06m}{(1.5kg)*(0.06)^2} $

\alpha  = 244.44\: s^{-2}

Therefore, the angular speed \omega which is

\omega  = \alpha t

after 6 seconds is

\omega = 244.44$\: s^{-2}* 6s

\boxed{\omega = 1466.67s^{-1}}

7 0
3 years ago
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