Able to be hammered or pressed permanently out of shape without breaking or cracking.
Answer:
J for impulse
t for time
F for force
formula is J=F×t
Explanation:
putting values in eqs after rearranging
we need to find force so
F=J ÷t
F=400÷15
=26.67
=27(rounded off)
27N is the Force applied.
Answer:
Initial velocity is 0 .. ( since it is just dropped)
now using V²= u² +2gh
=> (Vfinal)² = 0+2*10*20
=> v² = 20*20 = 400
=> v = √400 = 20m/s
for time taken
use V = u+gt
=> t = V/g = 20/10 = 2sec
Answer:
2,352 Joules
Explanation:
At the ground, the barbell has a classical mechanical energy value of zero. There is no classical kinetic or potential energy for the barbell. The moment the man starts to lift the barbell, he does work on the barbell and transfers kinetic energy to it due to the motion. At its maximum height where the man lifts the barbell to a stop, the kinetic energy is zero because it transformed into gravitational potential energy stored in the gravitational field. Our reference point for potential was defined to be zero at the floor, therefore we can say that the gravitational potential energy at 2 meters is:
