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3 years ago

when a solid wheel rotates about a fixed axis do all of the points of the wheel have the same tangential speed?

Physics

2 answers:

Gelneren [198K]3 years ago

4 0

Answer:

No - points with different radial distance from the center will experience different tangential speed.

Explanation:

Picture two points on the wheel: point A is very close (say, 1 mm) to the center, point B is further (say, 1m) away from the center. As the wheel makes one whole turn (2pi), both points will follow a circular trajectory, but point A will have traveled (2pi)x(0.001) meters and point B (2pi)x(1) meters in the same time. Point B's tangential velocity is therefore 1000 times greater than that of the point A.

The formula for tangential speed is as follows:

v = (angular velocity in radians/s) x (radius in m)

vitfil [10]3 years ago

3 0

Yes they should all be going the same speed.

Hope this helped :)

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A ball rolls 50 meters in

-Dominant- [34]

The speed of the ball is B. 5 meters per second

Explanation:

For an object in uniform motion (= at constant velocity), the speed can be calculated using the equation

$v=\frac{d}{t}$

where

v is the speed

d is the distance covered

t is the time taken

For the ball in this problem:

d = 50 m is the distance covered

t = 10 s is the time taken

Substituting, we find the speed:

$v=\frac{50}{10}=5 m/s$

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3 years ago

A movie stunt performer is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough

Julli [10]

Answer:

1125.66956 N

Explanation:

m = Mass of stunt performer

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of the swing = 7 m/s

T = Tension

r = Radius of the swing = Length of vine = 11.5 m

From the free body diagram

$T-mg-m\frac{v^2}{r}=0\\\Rightarrow T=mg+m\frac{v^2}{r}\\\Rightarrow T=m(g+\frac{v^2}{r})\\\Rightarrow T=80(9.81+\frac{7^2}{11.5})\\\Rightarrow T=1125.66956\ N$

The minimum tension force the vine must be able to support without breaking is 1125.66956 N

7 0

3 years ago

9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$