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Law Incorporation [45]
4 years ago
12

A car starting from rest accelerates at a rate of 8 0 m/s/s. What is its final speed at the end of 40 seconda?

Physics
2 answers:
erastovalidia [21]4 years ago
8 0

Answer: 320 m/s

Explanation:  V initial = 0, V final= ?   Acceleration = 8m/s/s  t=40s

<h3>So at the end of V 40 sec=  v intial + acceleration x Δt  = 0 +8m/s² x 40s  = 320m/s</h3>
Ilia_Sergeevich [38]4 years ago
3 0

Answer:

you have to organize the data. a= acceleration vi=inicial velocity vf=final velocity  t=time.

a=80m/s

vi=0

vf=?

t=40 s

the formula you have to use is:

vf=vi+a*t  (final velocity= inicial velocity plus acceleration times time)

Explanation:

I was the best one at my class, hope it helped

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The number of neutrons is equal to the atomic number<br> O A True<br> B. False
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Anarel [89]

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3 years ago
A small fan has blades that have a radius of 0.0600 m. When the fan is turned on, the tips of the blades have a tangential accel
zhuklara [117]

Answer:

α = 395 rad/s²

Explanation:

Main features of uniformly accelerated circular motion

A body performs a uniformly accelerated circular motion   when its trajectory is a circle and its angular acceleration is constant  (α = cte). In it the velocity vector is tangent at each point to the trajectory and, in addition, its magnitude varies uniformly.

There is tangential acceleration (at) and is constant.

at = α*R     Formula (1)

where

α  is the angular acceleration

R is the radius of the circular path

There is normal or centripetal acceleration that determines the change in direction of the velocity vector.

Data

R = 0.0600 m   :blade radius

at = 23.7 m/s² : tangential acceleration of the blades

Angular acceleration of the blades (α)

We replace data in the formula (1)

at = α*R  

23.7 = α*(0.06)

α = (23.7) / (0.06)

α = 395 rad/s²

7 0
3 years ago
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