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weqwewe [10]
3 years ago
15

What are the new vertices of parallelogram DEFG if the parallelogram is reflected across the vertical line x = -2, also graphed?

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Since x = - 2 is the line of reflection then the coordinates of the image will be the same distance in the x- direction from x = 2 but on the opposite side.

The y- coordinates of the points remain unchanged.

D is 3 units left of x = - 2 thus D' is 3 units to the right of x = - 2

E is 1 unit left of x = - 2 thus E' is 1 unit to the right of x = - 2

F is 1 unit left of x = - 2 thus F' is 1 unit to the right of x = - 2

G is 3 units left of x = - 2 thus G' is 3 units to the right of x = - 1

Thus

D(- 5, 5 ) → D'(1, 5 )

E(- 3, 3 ) → E'(- 1, 3 )

F(- 3, - 4 ) → F'(- 1, - 4 )

G(- 5, - 2 ) → G'(1, - 2 )

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Find the measure of the arc or central angle indicated. Assume that lines which appear to be diameters are actual diameters.
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If x=10, write an expression in terms of x for the number 5,364
LenKa [72]

Answer:

(5,354 + x)

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536.4*x

Step-by-step explanation:

We know that x = 10.

Now we want to write an expression (in terms of x) for the number 5,364.

This could be really trivial, remember that x = 10.

Then:  (x - 10) = 0

And if we add zero to a number, the result is the same number, then if we add this to 5,364 the number does not change.

5,364 = 5,364 + (x - 10) = 5,364 + x - 10

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3 years ago
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