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agasfer [191]
3 years ago
10

A solid concrete block weighs 140 N and is resting on the ground. Its dimensions are 0.370 m x 0.150 m x 0.0820 m. A number of i

dentical blocks are stacked on top of this one. What is the smallest number of whole bricks (including the one on the ground) that can be stacked so that their weight creates a pressure of at least two atmospheres on the ground beneath the first block? (Hint: First decide which face of the brick is in contact with the ground.)
Physics
1 answer:
belka [17]3 years ago
5 0

Answer: 18 blocks in total ( 17 add to the original in contact with the ground)

Explanation:

The pressure on the face in contact with the ground ( we choose the face 0.15m x 0.082m)

Pressure= Force ( weigth) /Area

1 Atm = 101325 Pascal [N/ m^2]

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5 0
2 years ago
I need help with this please
kondaur [170]

Answer:

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Explanation:

6 0
2 years ago
The ovaries in females and the testes in males are part of the
antoniya [11.8K]

Answer:

Gonads

Explanation:

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Hope this helps :)

3 0
3 years ago
Why does a box on the seat of a car slide around on the c one the car speeds up slows down or turns a corner?
Feliz [49]
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8 0
2 years ago
Starting from rest, a 6.79 kg block slides 2.82 m down a rough 20.7 ◦ incline. The coefficient of kinetic friction between the b
Veronika [31]

Answer:

23.52092 J

Explanation:

m = Mass of block = 6.79 kg

s = Sliding distance = 2.82 m

\theta = Angle of slide = 20.7°

\mu = Coefficient of kinetic friction = 0.425

g = Acceleration due to gravity = 9.8 m/s²

Work done by the force of gravity is given by

W=mgsin\theta\\\Rightarrow W=6.79\times 9.8\times sin20.7\\\Rightarrow W=23.52092\ J

The work done by the force of gravity is 23.52092 J

8 0
2 years ago
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