12.0 min = 720. s
so the distance covered moving at a constant 15.0 m/s is
(15.0 m/s) (720. s) = 10,800 m = 10.8 km = 1.08 × 10¹ km
<span>Work=32unit</span><span>...hopes thats helps</span>
Because the momentum would still be applied to the orange if the tray stopped moving
Answer:
the height of the bridge above the water is 49.6 m.
Explanation:
Given;
initial velocity of the stone, u = 15 m/s
time of motion of the stone, t = 2 s
The height of the bridge above the water is calculated from the following kinematic equation as follows;
h = ut + ¹/₂gt²
h = (15 x 2) + ¹/₂(9.8)(2²)
h = 30 + 19.6
h = 49.6 m
Therefore, the height of the bridge above the water is 49.6 m.
Let
A = the amplitude of vibration
k = the spring constant
m = the mass of the object
The displacement at time, t, is of the form
x(t) = A cos(ωt)
where
ω = the circular frequency.
The velocity is
v(t) = -ωA sin(ωt)
The maximum velocity occurs when the sin function is either 1 or -1.
Therefore
Therefore
The KE (kinetic energy) is given by
The PE (potential energy) is given by
When the KE and PE are equal, then
For the oscillating spring,
Therefore
Answer: