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Romashka [77]
3 years ago
15

A toy car has an initial acceleration of 2 m/s" across a horizontal surface after it is released from rest. After the car travel

s for a timet
consisting of only the car an open system or a closed system, and why?
Open system because the acceleration of the car is not constant.
Open system, because an external force is applied to the car that causes it to accelerate.
Closed system, because the speed of the car is as expected in the case where an object has uniform acceleration for a timet
Closed system because mechanical energy was not removed from the system as a result of a net force
Rie
B
7:53 PM
12/11/2019
Physics
2 answers:
Ganezh [65]3 years ago
3 0

Answer:

Closed system, because the speed of the car is as expected in the case where an object has uniform acceleration for a time t

Explanation:

Here in the question it is mentioned that a toy car has an initial acceleration of 2m/s²  across a horizontal surface so we can say that it is acted upon by an external force

Assuming that the acceleration is constant and the reason for this assumption is there at the last

The major difference between an open system and closed system is in case of open system there will be transfer of matter and in case of closed system there will be no change in matter of the system

If acceleration is constant in case of closed system we can expect the speed of the car after a time t by using the formula

  s = u×t + 0·5×a×t²

where s is the distance travelled

t is the time taken to travel that distance

u is the initial velocity

a is the acceleration of that system

But in case of open system as there will be a change of mass there will be a change in velocity of the system so in this case we cannot expect the speed of the car after a time t

And if the acceleration is not constant then we cannot say that the toy car is an open system or closed system, that is why we are assuming that the acceleration of the toy car is constant

ycow [4]3 years ago
3 0

Answer:

Open system, because an external force is applied to the car that causes it to accelerate.

Explanation:

A system is a space in the universe that is separated for study. It can be closed or open. A closed system is systems that aren't affected by external forces, and also didn't change the energy of the surroundings. An open system, on the other hand, is affected by external forces or change energy with the surroundings.

In this case, if only the toy car is the system, we can assume it as an open system, because an external force had to be done to it, so it could be in movement. In other words, an external force is applied to the car that causes it to accelerate.

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Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before the collision, puck 1 is going 13 m/s to the east and
ohaa [14]

Answer:

13 m/s east

Explanation:

We can solve the problem by using the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision:

p_i = p_f \\m u_1 + m u_2 = m v_1 + m v_2

where

m = 0.1 kg is the mass of each puck

u1 = +13 m/s is the initial velocity of puck 1

u2 = -18 m/s is the initial velocity of puck 2 (here I assume the west direction to be the negative direction, so I put a negative sign)

v1 = -18 m/s is the final velocity of puck 1

v2 = ? is the final velocity of puck 2

Simplifying m from the formula and substituting the data, we can find the final velocity of puck 2, v2:

v_2 = u_1 + u_2 - v_1 = +13 m/s + (-18 m/s) - (-18 m/s) = +13 m/s

And the positive sign means that puck 2 is moving east.

4 0
2 years ago
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What do electric power companies deliver to customers
kvv77 [185]

Answer:

Power plants generate electricity that is delivered to customers through transmission and distribution power lines. High-voltage transmission lines, such as those that hang between tall metal towers, carry electricity over long distances to meet customer needs.

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8 0
3 years ago
Two speedboats can each travel at V= 5 m/s with respect to water. One boat crosses the
charle [14.2K]
Consider the travel of the speedboat from A to B and back.
Refer to the first figure.
The boat travels at 5 m/s relative to the water, and the downstream speed of the water is 0.5 m/s.
Therefore,
V₁=5 m/s, u = 0.5 m/s, sinθ = 0.5/5 = 0.1 => θ = arcsin(0.1) = 5.74°.
The boat should travel upstream at 5 m/s, at an angle of 5.74°.

Similarly, return speed from B to A is 5 m/s, at 5.74° upstream.

The horizontal component of velocity from A to B (or vice versa) is 
5cos(5.74°) = 4.975 m/s.

The time required to travel 1000 m is
1000/4.975 = 202.02  = 3.367 min.
The time for the return trip is
t₁ = 2*3.367 = 6.734 min.

Consider travel from C to D and back, as shown in the second figure.
The resultant velocity upstream from C to D is
V₁ = 5 - 0.5 = 4.5 m/s
The time required to travel 1000 m fromC to D is
1000/4.5 = 222.22 s

The resultant velocity downstream from D to C is
V₂ = 5 + 0.5 = 5.5 m/s
The time required to travel fro D to C is 
1000/5.5 = 181.82 s
Total time for the return trip between C and D is
t₂ = 222.22 + 181.82 = 404.04 s = 6.734 min

Answer:
The first boat should travel upstream at an angle of 5.74°. The time for the return trip between A and B is t₁ = 6.734 min or 404.04 s.

The second boat travels upstream against the current, and downstream with the current. The time for the return trip between C and D is t₂ = 6.734 min or 404.04 s.

5 0
3 years ago
a box has a momentum of 1.30 kg*m/s to the right. a 12.8 N force pushes it to the right for 0.218 s. what is the final momentum
Rufina [12.5K]

Answer:

4.09 kgm/s

Explanation:

Concept tested: Second Newton's law of motion

So what does the second Newton's law of motion state?

  • According to the second Newton's law of motion, the resultant force and the rate of change of momentum are directly proportional.
  • That is; F=\frac{(mVf-mVo)}{t}, where, mVf is the final momentum and mVo is the initial momentum.

In this case;

  • Force = 12.8 N
  • Initial momentum, mVo = 1.3 kgm/s
  • Time, t = 0.218 seconds

Therefore; replacing the values of the variables in the formula;

we get;

12.8N=\frac{(mVf-1.3kgm/s)}{0.218s}

(12.8N)(0.218s)=(mVf-1.3kgm/s)

2.7904+1.3=mVf

Solving for final momentum;

mVf =4.0904 kgm/s

      = 4.09 kgm/s

Therefore, the final momentum of the box is 4.09 kgm/s

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Period, that's the solution
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3 years ago
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