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leva [86]
3 years ago
11

I need help with this

Physics
1 answer:
lord [1]3 years ago
7 0

Answer:

0.832

Explanation:

8.320 x 10 to the negative 1st power is 0.832

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PLEASE HELP ME WITH MY HOMEWORK!!!!!
IgorC [24]

Known :

l = 7 cm

w = 4 cm

Asked :

h = ...?

Answer :

V = B triangle × h (long)

35 = ½ × 4 × h × 7

35 = ½ × 28 × h

35 = 14 h

h = 35 ÷ 14

h = 2,5 cm

Sorry if I am wrong, I only study

5 0
3 years ago
Blake is setting up his tent at a renaissance fair. If the tent is 8 feet tall and the tether can be staked no more than 2 feet
Mariana [72]
The stake, height and tether length of the tent form a right angle triangle where the tether length is the hypotenuse.
Applying Pythagoras theorem:
length² = height² + (stake distance)²
length = √(8² + 2²)
length = 8.5 feet
3 0
3 years ago
A skier is accelerating down a 30.0-degree hill at 3.80 m/s^2.
Bond [772]

Answer:

ax = -3.29[m/s²]

ay = -1.9[m/s²]

Explanation:

We must remember that acceleration is a vector and therefore has magnitude and direction.

In this case, it is accelerating downwards, therefore for a greater understanding we will make a diagram of said vector, this diagram is attached.

a_{x}=-3.8*cos(30) = -3.29 [m/s^{2}]\\ a_{y}=-3.8*sin(30) = -1.9 [m/s^{2}]

3 0
3 years ago
4. Think back to Coulomb's Law. Two coins with identical charges are placed on a lab table 1.35 m apart.
FinnZ [79.3K]
A) To calculate the charge of each coin, we must apply the expression of the Coulomb's Law:
 
 F=K(q1xq2)/r²
 
 F: The magnitud of the force between the charges. (F=2.0 N).
 K: Constant of proporcionality of the Coulomb's Law (K=9x10^9 Nxm²/C²).
 q1 and q2: Electrical charges.
 r: The distance between the charges (r=1.35 m).
 
 We have the values of F, K and r, so we can calculate q1xq2, because both<span> coins have  identical charges:
</span> 
 q1xq2=(r²xF)/K
 q1xq2=(1.35 m)²(2.0 N)/9x10^9 Nxm²/C²
 q1xq2=3x10^-10 C
 q1=q2=(<span>3x10^-10 C)/2
 
 </span>Then, the charge of each coin, is:
<span> 
 q1=1.5x</span><span>10^-10 C 
 
 </span>q2=1.5x10^-10 C

B) <span>Would the force be classified as a force of attraction or repulsion?
</span> 
 It is a force of repulsion, because both coins have identical charges and both are postive. In others words, when two bodies have identical charges (positive charges or negative charges), the force is of repulsion.
5 0
3 years ago
Read 2 more answers
You have two vectors, which are 2.59 m at 30.0° north of east and 4.18 m at 60.0° north of west. What is the magnitude in meters
andrew11 [14]

Answer:\ec{r}=0.153\hat{i}+4.914\hat{j}v

Explanation:

Given

Vector 1

\vec{a}=2.59\left ( cos30\hat{i}+sin30\hat{j}\right )

Vector 2

\vec{b}=4.18\left ( -cos60\hat{i}+sin60\hat{j}\right )

Resultant \vec{r}=\vec{a}+\vec{b}

\vec{r}=2.59\left ( cos30\hat{i}+sin30\hat{j}\right )+4.18\left ( -cos60\hat{i}+sin60\hat{j}\right )

\vec{r}=0.153\hat{i}+4.914\hat{j}

|r|=4.916

5 0
3 years ago
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