3 years ago

I need help with this

Physics

1 answer:

lord [1]3 years ago

7 0

Answer:

0.832

Explanation:

8.320 x 10 to the negative 1st power is 0.832

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Answer:

Q=1.42 C

Explanation:

Given that

$I=I_oe^{\dfrac{-t}{\tau}}$

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We know that

$I=\dfrac{dQ}{dt}$

Q=Charge ,I =Current

Q = ∫I.dt

Given that

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The charge Q

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Transverse waves are sent along a 4.50 m long string with a speed of 85.00 m/s. The string is under a tension of 20.00 N. What i

frutty [35]

Answer:

m = 0.0125 kg

Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

$v = \sqrt{\frac{F}{\mu} }$

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μ = mass per unit length

Mass per unit length is given as:

μ = m / l

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l = length of the string

This implies that:

$v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }$

Let us make mass, m, the subject of the formula:

$v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}$

From the question:

F = 20 N

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jk thx for the points thoo

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